Yeah, base is ten and the two sides are 5...
Answer:
let the larger and smaller number be x and y respectively
first condition
x + y = 49
second condition
3x = 2y+97
3x-2y =97
Multiplying first condition by two and adding both equations
2x + 2y = 98
<u>3x -2y = 97</u>
5x = 195
x = 195/5 = 39
putting the value of x in
x + y = 49
y = 49 -39 = 10
again
Step-by-step explanation:
9514 1404 393
Answer:
- (c1, c2, c3) = (-2t, 4t, t) . . . . for any value of t
- NOT linearly independent
Step-by-step explanation:
We want ...
c1·f1(x) +c2·f2(x) +c3·f3(x) = g(x) ≡ 0
Substituting for the fn function values, we have ...
c1·x +c2·x² +c3·(2x -4x²) ≡ 0
This resolves to two equations:
x(c1 +2c3) = 0
x²(c2 -4c3) = 0
These have an infinite set of solutions:
c1 = -2c3
c2 = 4c3
Then for any parameter t, including the "trivial" t=0, ...
(c1, c2, c3) = (-2t, 4t, t)
__
f1, f2, f3 are NOT linearly independent. (If they were, there would be only one solution making g(x) ≡ 0.)
You would move the decimal point two times to the left for the decimal. 0.076
For the fraction, we would make it 76/1000 because the 6 converted in the decimal is in the thousandth place. We can simplify it and get 19/250.
We are asked to perform the long division on the following expression.

Let us perform the long division.
So, we have
Quotient: q(x) = 19x^2 - 24x + 30
Remainder: r(x) = -32
Divisor: b(x) = x + 1
Therefore, the equivalent expression is

The 3rd option is the correct answer.