If tan theta is -1, we know immediately that theta is in either Quadrant II or Q IV. We need to focus on Q IV due to the restrictions on theta.
Because tan theta is -1, the ray representing theta makes a 45 degree angle with the horiz axis, and a 45 degree angle with the negative vert. axis. Thus the hypotenuse, by the Pythagorean Theorem, tells us that the hyp is sqrt(2).
Thus, the cosine of theta is adj / hyp, or +1 / sqrt(2), or [sqrt(2)]/2
The secant of theta is the reciprocal of that, and thus is
2 sqrt(2)
---------- * ------------ = sqrt(2) (answer)
sqrt(2) sqrt(2)
P=18
l=5 cm greater than the width
w=5 less than the length
USE YOUR NUMBER SENSE!!! - just plug in different number below 4 to figure out the width
3=w 3+5=8 8+8=16+6=22 WILL NOT WORK
2=w 2+5=7 7+7=14 14+2+2= 18 WE HAVE A WINNER!!!!
FInal Answer: width: 2 cm and length: 7 cm
Answer:
3
Step-by-step explanation:
The principal, real, root of:
![\sqrt[2]{3}](https://tex.z-dn.net/?f=%5Csqrt%5B2%5D%7B3%7D)
=1.73205081
All roots:
1.73205081
−1.73205081
3 is not a perfect square
