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Irina-Kira [14]
4 years ago
12

What is the answer to -12(-2-4x)

Mathematics
2 answers:
erica [24]4 years ago
6 0

Answer: OK so you should

Step-by-step explanation:

Use math papa.com for help dm me if u need the link

dimaraw [331]4 years ago
4 0

Hey there!☺

Answer:\boxed{48x+24}

Explanation:

-12(-2-4x)

You will need to simplify the expression to solve.

-12(-2-4x)\\48x+24

48x+24 is your final answer.

Hope this helps!

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alexgriva [62]
The scale factor would be used in solving for the volume inside the larger chest. By definition, a scale factor is considered to be the ratio of similar sides of similar figures. By using this method:

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Please help!! What is 6(4 - y) = 5 + 3?
Archy [21]

Answer:

<h3>\boxed{ \boxed{ \bold{ \sf{2.6}}}}</h3>

Step-by-step explanation:

\sf{6(4 - y) = 5 + 3}

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\sf{24 - 6y = 5 + 3}

Add the numbers

\sf{24 - 6y = 8}

Move constant to right hand side and change it's sign

\sf{ - 6y = 8 - 24}

Calculate

\sf{ - 6y =  - 16}

Divide both sides of the equation by -6

\sf{ \frac{ - 6y}{ - 6}  =  \frac{ - 16}{ - 6} }

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3 years ago
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2. Graph the following equation: y = - 1/2 x + 4
Murljashka [212]

Answer:

Step-by-step explanation:

y = (-1/2)x + 4 is the equation of a straight line with y-intercept (0, 4) and slope -1/2.

To graph this, first plot the y-intercept (0, 4).

Recall that slope m = rise / run, and notice that the slope in this particular case is -1/2 = rise / run, or rise = -1 and run = 2.

Starting with your pencil point on (0, 4), move the point 2 units to the right (run = 2), arriving at (2, 4).  Next, move your pencil point 1 unit down, to (2, 3).

Draw a straight line through (0, 4) and (2, 3).

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3 years ago
Please help me with this Algebra I question.
horrorfan [7]

Answer:

-\dfrac{b^2}{16a^4}

Step-by-step explanation:

Given expression:

\dfrac{(2a)^{-2}b^5}{-4a^2b^3}

\textsf{Apply the exponent rule}\quad (ab)^c=a^c \cdot b^c:

\implies \dfrac{2^{-2}a^{-2}b^5}{-4a^2b^3}

Separate the variables:

\implies \dfrac{2^{-2}}{-4}\cdot \dfrac{a^{-2}}{a^2}\cdot \dfrac{b^5}{b^3}

\textsf{Apply the exponent rule} \quad \dfrac{a^b}{a^c}=a^{b-c}:

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\implies \dfrac{2^{-2}}{-4}\cdot a^{-4}\cdot b^{2}

\textsf{Apply the exponent rule}\quad a^{-n}=\dfrac{1}{a^n}:

\implies \dfrac{1}{-4(2^2)}\cdot \dfrac{1}{a^4}\cdot b^{2}

\implies -\dfrac{1}{16}\cdot \dfrac{1}{a^4}\cdot b^{2}

Simplify:

\implies -\dfrac{b^2}{16a^4}

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2 years ago
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