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const2013 [10]
3 years ago
5

Y = 2x( z+ 3 ) find y if z = 2 and x = 4 whats the formula​

Mathematics
1 answer:
Ede4ka [16]3 years ago
4 0

Answer:

hi there!

the answer to this question y=40

Step-by-step explanation:

you plug each variable into the equation:

y= (2*4) * ( 2+3)

you use the steps of PEMDAS

Parenthesis Exponent Multiplication Division Addition Subtraction

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If angle 1 and angle 2 form linear pair and m angle 1 =50, then m angle = 2
Irina-Kira [14]
Measure of angle 2 would be 130 degrees because since it forms a linear pair the two angles added together have to equal 180 degrees so 
180 - 50 = 130
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4 years ago
Doc Brown’s DeLorean has three crucial systems that are required for a successful trip: combustion engine, time circuits, and fl
Nesterboy [21]

Step-by-step explanation:

The total probability that the DeLorean makes the trip is:

P = P(engine) × P(at least 1 time circuit) × P(at least 2 capacitors)

P = P(engine) × (1 − P(0 time circuits)) × P(at least 2 capacitors)

P = 0.94 × (1 − ₄C₀ 0.75⁰ 0.25⁴) × (₃C₂ 0.8² 0.2¹ + ₃C₃ 0.8³ 0.2⁰)

P = 0.94 × (1 − 0.25⁴) × (0.384 + 0.512)

P = 0.83895

The reliability of the DeLorean is approximately 83.9%.

3 0
4 years ago
There are 6 showings of a film about Van Gogh at the art museum. A total of 459 people saw the film. The same number of people w
Strike441 [17]

Answer:

548

Step-by-step explanation:

its obvious

8 0
3 years ago
What are the coordinates of the orthocenter of △JKL with vertices at J(−4, −1) , K(−4, 8) , and L(2, 8) ?
Sati [7]

<u>Answer-</u>

<em>The coordinates of the orthocenter of △JKL is (-4, 8)</em>

<u>Solution-</u>

The orthocenter is the point where all three altitudes of the triangle intersect. An altitude is a line which passes through a vertex of the triangle and is perpendicular to the opposite side.

For a right angle triangle, the vertex at the right angle is the orthocentre of the triangle.

Here we are given the three vertices of the triangle are  J(-4,-1), K(-4,8) and L(2,8)

If the triangle JKL satisfies Pythagoras Theorem, then triangle JKL will be a right angle triangle.

Applying distance formula we get,

JK^2= (-4+4)^2+ (8+1)^2=0+81=81\\\\KL^2= (-4-2)^2+ (8-8)^2=36+0=36\\\\JL^2= (-4-2)^2+(8+1)^2=36+81=117

As,

\Rightarrow 117=81+36

\Rightarrow JL^2=JK^2+KL^2

\Rightarrow \text{JKL is a right angle triangle}

\Rightarrow \angle K=90^{\circ}

Therefore, the vertex at K (-4, 8) is the orthocentre.

3 0
3 years ago
What is the domain of f(x) = 5"?<br> ASAP
Damm [24]

Answer:

domain is all real number

8 0
3 years ago
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