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2 years ago

-26 =3v +1 can i please get a answer

Mathematics

2 answers:

garik1379 [7]2 years ago

5 0

Answer:

v = -9

Step-by-step explanation:

ur welcome

Rufina [12.5K]2 years ago

3 0

Step-by-step explanation:

-26=3v+1

-1 on both sides

-27=3v

divide by 3 both sides

-9=v

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Please help with this question.

barxatty [35]

Answer:

Step-by-step explanation:

The first thing we have to do is find the measure of angle A using the fact that the csc A = 2.5.

Csc is the inverse of sin. So we could rewrite as

$\frac{1}{sinA}=2.5$ or more easy to work with is this:

$\frac{1}{sinA} =\frac{2.5}{1}$

and cross multiply to get

2.5 sinA = 1 and

$sinA=\frac{1}{2.5}$ which simplifies to

sin A = .4

Using the 2nd and sin keys on your calculator, you'll get that the measure of angle A is 23.58 degrees.

We can find angle B now using the Triangle Angle-Sum Theorem that says that all the angles of a triangle have to add up to equal 180. Therefore,

angle B = 180 - 23.58 - 90 so

angle B = 66.42

The area of a triangle is

$A =\frac{1}{2}bh$ where h is the height of the triangle, namely side AC; and b is the base of the triangle, namely side BC. To find first the height, use the fact that angle B, the angle across from the height, is 66.42, and the hypotenuse is 3.9. Right triangle trig applies:

$sin(66.42)=\frac{h}{3.9}$ and

3.9 sin(66.42) = h so

h = 3.57

Now for the base. Use the fact that angle A, the angle across from the base, measures 23.58 degrees and the hypotenuse is 3.9. Right triangle trig again:

$sin(23.58)=\frac{b}{3.9}$ and

3.9 sin(23.58) = b so

b = 1.56

Now we can find the area:

$A=\frac{1}{2}(1.56)(3.57)$ so

A = 2.8 cm squared

3 0

2 years ago

Suppose 300 nursing students took a certification test that is worth 100 points.

Alja [10]

Answer:

225 students scored 65 or better and 75 students scored 88 or better.

Step-by-step explanation:

We are given that The five-number summary for the scores of 300 nursing students are given :

Minimum = 40

$Q_1 = 65$

Median = 82

$Q_3 = 88$

Maximum = 100

$Q_1$ is the first quartile and is the median of the lower half of the data set. 25% of the numbers in the data set lie below $Q_1$ and about 75% lie above $Q_1$ .

$Q_3$ is the third quartile and is the median of the upper half of the data set. 75% of the numbers in the data set lie below $Q_3$ and about 25% lie above $Q_3$