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zzz [600]
3 years ago
6

In February, Campus Cycle Repair had income from sales of $16,000. Expenses for the month included: rent, $1,250; utilities, $45

0; employee wages, $4,800; insurance, $300; parts and supplies, $2,700. The owner also incurs a monthly franchise fee equal to 5 percent of income from sales. What is the amount of profit (or loss) earned by Campus Cycle Repair for the month of February.
Mathematics
1 answer:
djyliett [7]3 years ago
5 0

Answer:

Profit $5700

Step-by-step explanation:

To find loss/profit you subtract the expenses from the total income

Income from sales= $16000

Franchise fee= 5% of sales income

=\frac{5}{100} *16000=800

Rent=$1250

Utilities=$450

Wages=$4800

insurance=$300

supplies=$2700

Total expenses

=$1250+$450+$4800+$300+$2700+$800=$10300

Total income

=$16000

Profit

=$16000-$10300=$5700

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When is 9+10 really equal to 21
schepotkina [342]

Answer:

9 + 10 = 21

Step-by-step explanation:

9 + 10 = 21

Factor out 9 and 10

9 = 3 · 3   10 = 2 · 5

Next multiply 3 by 2

3 × 2 = 6

Then multiply 3 by 5

3 · 5 = 15

Finally add the products

15 + 6 = 21

4 0
3 years ago
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What is the first step to solve this equation:<br> -3x + 12 = -40
ElenaW [278]

Answer:

Your supposed to cancel out 12 on both sides so u subtract 12 on both sides so the equation would be

-3x= -52

Step-by-step explanation:

7 0
2 years ago
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Consider the initial value problem y′+2y=4t,y(0)=8.
Xelga [282]

Answer:

Please read the complete procedure below:

Step-by-step explanation:

You have the following initial value problem:

y'+2y=4t\\\\y(0)=8

a) The algebraic equation obtain by using the Laplace transform is:

L[y']+2L[y]=4L[t]\\\\L[y']=sY(s)-y(0)\ \ \ \ (1)\\\\L[t]=\frac{1}{s^2}\ \ \ \ \ (2)\\\\

next, you replace (1) and (2):

sY(s)-y(0)+2Y(s)=\frac{4}{s^2}\\\\sY(s)+2Y(s)-8=\frac{4}{s^2}  (this is the algebraic equation)

b)

sY(s)+2Y(s)-8=\frac{4}{s^2}\\\\Y(s)[s+2]=\frac{4}{s^2}+8\\\\Y(s)=\frac{4+8s^2}{s^2(s+2)} (this is the solution for Y(s))

c)

y(t)=L^{-1}Y(s)=L^{-1}[\frac{4}{s^2(s+2)}+\frac{8}{s+2}]\\\\=L^{-1}[\frac{4}{s^2(s+2)}]+L^{-1}[\frac{8}{s+2}]\\\\=L^{-1}[\frac{4}{s^2(s+2)}]+8e^{-2t}

To find the inverse Laplace transform of the first term you use partial fractions:

\frac{4}{s^2(s+2)}=\frac{-s+2}{s^2}+\frac{1}{s+2}\\\\=(\frac{-1}{s}+\frac{2}{s^2})+\frac{1}{s+2}

Thus, you have:

y(t)=L^{-1}[\frac{4}{s^2(s+2)}]+8e^{-2t}\\\\y(t)=L^{-1}[\frac{-1}{s}+\frac{2}{s^2}]+L^{-1}[\frac{1}{s+2}]+8e^{-2t}\\\\y(t)=-1+2t+e^{-2t}+8e^{-2t}=-1+2t+9e^{-2t}  

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5 0
3 years ago
The diagram shows one way to develop the formula for the area of a circle. Pieces of a circle with radius r are rearranged to cr
podryga [215]

Question:

a. A = (2πr)(r)

b. A = (2πr)(2r)

c. A =\frac{1}{2} (2\pi r)(r)

d. A =\frac{1}{2} (2\pi r)(2r)

Answer:

The correct option is A =\frac{1}{2} (2\pi r)(r)

Step-by-step explanation:

The formula for the area, A of a parallelogram = base, b × height, h

Therefore, since the base dimension is approximately half the perimeter of a circle, we have;

Base, b = 2·π·r × 1/2

Where the height of the parallelogram, as shown in the diagram is approximately the radius of the circle, we have;

Height, h = r

Therefore, the approximate area, A of the parallelogram is given by the following relation;

A = b × h =  2·π·r × 1/2 × r Which is the same as A = \frac{1}{2} (2\pi r)(r).

4 0
2 years ago
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Leno4ka [110]
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34*16 = 544.

544 ounces > 534 ounces, so 34 pounds > 534 ounces.
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3 years ago
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