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Fudgin [204]
3 years ago
7

The length of a rectangle is twice the width. An equation that models the perimeter of the rectangle is 2w+4w=36 where w is the

width of the rectangle is ft. What are the length and width of the rectangle?
Mathematics
2 answers:
notka56 [123]3 years ago
7 0

Answer:

shes right the person ahade of me

drek231 [11]3 years ago
4 0

Answer: 12

Step-by-step explanation:

Let w = the width of the rectangle

Let 2w = the length

P = 2l + 2w

36 = 2(2w) + 2w

36 = 4w + 2w

36 = 6w

w = 6

l = 2(6)

l = 12

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Answer:

Rounding it to two decimal places, we get distance, d=17.35

Step-by-step explanation:

Given:

The two points are (9.7, -2.8)\textrm{ and }(-3.2, 8.8)

The distance between the two points can be obtained using the distance formula which is given as:

d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Here, for the points, (9.7, -2.8)\textrm{ and }(-3.2, 8.8)

x_{1}=9.7,x_{2}=-3.2,y_{1}=-2.8,y_{2}=8.8

Therefore, the distance between the points is:

d=\sqrt{(-3.2-9.7)^2+(8.8-(-2.8))^2}\\d=\sqrt{(-12.9)^2+(8.8+2.8)^2}\\d=\sqrt{(12.9)^2+(11.6)^2}\\d=\sqrt{166.41+134.56}\\d=\sqrt{300.97}=17.348

Rounding it to two decimal places, we get d=17.35

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