What is the correct structure for 7-bromo-5-octyn-3-one?
1 answer:
The correct structure is shown below,
According to rules the longest carbon chain is selected, and numbering is started from side nearer to carbonyl group. As the parent name goes to ketone, so among alkyne and halogen second priority is given to alkyne and 3rd to halogen
So, the name shoul carry following words,
3- one (for ketone)
5-yne (for Alkyne)
7-Bromo (for Halogen)
Result:
So the structure is as follow,
According to rules the longest carbon chain is selected, and numbering is started from side nearer to carbonyl group. As the parent name goes to ketone, so among alkyne and halogen second priority is given to alkyne and 3rd to halogen
So, the name shoul carry following words,
3- one (for ketone)
5-yne (for Alkyne)
7-Bromo (for Halogen)
Result:
So the structure is as follow,
You might be interested in
Answer:
NH₂⁻<NH₃<NH₄⁺
Explanation:
Hello.
In this case, regarding the molecules:
NH₄⁺, NH₃ and NH₂⁻.
Which are ammonium, ammonia and amide, in order to rank them in terms of how big the angles are, we need their molecular geometry as shown on the attached picture. As you can see, the geometry of ammonium is tetrahedral with an angle between H bonds of 109.5°, the geometry of ammonia is trigonal pyramidal with an angle between H bonds of about 107° and the geometry of amide is bent with angles of 104.5°.
Therefore the order from smallest to biggest is: NH₂⁻<NH₃<NH₄⁺.
Best regards.
