Answer
let the first number be x
second number be y
5*(x)+y=-21---------->equation 1
2*(x)+y=-9------------->equation2
<h2>
eq1 * 2:</h2>
2(5x+y)=2*-21
10x+2y=-42
<h2>
eq2 * 5:</h2>
10x+5y=-45
10x+2y=-42
-(10x+5y=-45)
-----------------
0 - 3y=3
y=3/-3
<h2>
y=-1</h2><h3>
sub y=-1 in eq1;</h3><h3>
5x+y=-21</h3><h3>
5x+ -1=-21</h3><h3>
5x-1=-21</h3><h3>
5x=-21+1</h3><h3>
5x=20</h3><h3>
x=20/5</h3><h2>
x=4</h2><h2>
y=-1</h2>
Answer:
X is a discrete Random variable where X is the number of races Jockey can win.
Step-by-step explanation:
To find - A jockey will ride horses in 10 different races at a race track today.
The number of races that the jockey will win is what type of random variable ?
Proof -
Given that,
A jockey will ride horses in 10 different races at a race track today.
Let us assume that,
X is the number of races Jockey can win
So,
X can take value 0, 1, 2, 3, ......10
As,
It can take countable finite values
So,
X is a discrete Random variable
∴ we get
X is a discrete Random variable where X is the number of races Jockey can win.
Its most likely probably going to maybe be no just kidding its actu
Answer:
We need the table
Step-by-step explanation: