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melisa1 [442]
3 years ago
6

In the typing world,80 words per minute is considered acceptable.how many words per 30 minutes is this

Mathematics
1 answer:
lukranit [14]3 years ago
8 0
W = words per minute = 80
t = time in minutes = 30

The total number of words per 30 minutes is w*t = 80*30 = 2400 words
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a rectangle has a length of 8m and a width of 4.5m. A parallelogram has a length of 6 m. The area of the parallelogram is twice
Tcecarenko [31]

Answer:

12m

Step-by-step explanation:

work out the area of the rectangle then times it by 2 because the parallelogram is twice the area of the rectangle. 8 × 4.5m = 36m². 36 ×2 = 72cm². Now you do 72 ÷ 6 = 12 . the answer is 12m.

6 0
3 years ago
Can someone please help me
Aleks04 [339]
The answer is D. 60/100

In order to get the denominator from 5 to 100, you must multiple it by 20, meaning you also have to do that to the numerator. 3x20=60, therefore, the answer is 60/100
3 0
3 years ago
Maths functions question!!
Marina86 [1]

Answer:

5)  DE = 7 units and DF = 4 units

6)  ST = 8 units

\textsf{7)} \quad \sf OM=\dfrac{3}{2}\:units

8)  x ≤ -3 and x ≥ 3

Step-by-step explanation:

<u>Information from Parts 1-4:</u>

brainly.com/question/28193969

  • f(x)=-x+3
  • g(x)=x^2-9
  • A = (3, 0)  and C = (-3, 0)

<h3><u>Part (5)</u></h3>

Points A and D are the <u>points of intersection</u> of the two functions.  

To find the x-values of the points of intersection, equate the two functions and solve for x:

\implies g(x)=f(x)

\implies x^2-9=-x+3

\implies x^2+x-12=0

\implies x^2+4x-3x-12=0

\implies x(x+4)-3(x+4)=0

\implies (x-3)(x+4)=0

Apply the zero-product property:

\implies (x-3)= \implies x=3

\implies (x+4)=0 \implies x=-4

From inspection of the graph, we can see that the x-value of point D is <u>negative</u>, therefore the x-value of point D is x = -4.

To find the y-value of point D, substitute the found value of x into one of the functions:

\implies f(-4)=-(-4)=7

Therefore, D = (-4, 7).

The length of DE is the difference between the y-value of D and the x-axis:

⇒ DE = 7 units

The length of DF is the difference between the x-value of D and the x-axis:

⇒ DF = 4 units

<h3><u>Part (6)</u></h3>

To find point S, substitute the x-value of point T into function g(x):

\implies g(4)=(4)^2-9=7

Therefore, S = (4, 7).

The length ST is the difference between the y-values of points S and T:

\implies ST=y_S-y_T=7-(-1)=8

Therefore, ST = 8 units.

<h3><u>Part (7)</u></h3>

The given length of QR (⁴⁵/₄) is the difference between the functions at the same value of x.  To find the x-value of points Q and R (and therefore the x-value of point M), subtract g(x) from f(x) and equate to QR, then solve for x:

\implies f(x)-g(x)=QR

\implies -x+3-(x^2-9)=\dfrac{45}{4}

\implies -x+3-x^2+9=\dfrac{45}{4}

\implies -x^2-x+\dfrac{3}{4}=0

\implies -4\left(-x^2-x+\dfrac{3}{4}\right)=-4(0)

\implies 4x^2+4x-3=0

\implies 4x^2+6x-2x-3=0

\implies 2x(2x+3)-1(2x+3)=0

\implies (2x-1)(2x+3)=0

Apply the zero-product property:

\implies (2x-1)=0 \implies x=\dfrac{1}{2}

\implies (2x+3)=0 \implies x=-\dfrac{3}{2}

As the x-value of points M, Q and P is negative, x = -³/₂.

Length OM is the difference between the x-values of points M and the origin O:

\implies x_O-x_m=o-(-\frac{3}{2})=\dfrac{3}{2}

Therefore, OM = ³/₂ units.

<h3><u>Part (8)</u></h3>

The values of x for which g(x) ≥ 0 are the values of x when the parabola is above the x-axis.

Therefore, g(x) ≥ 0 when x ≤ -3 and x ≥ 3.

8 0
11 months ago
Read 2 more answers
What is the constant in the expression 4x + 2
rosijanka [135]

Answer:

the constant is 2

Step-by-step explanation:

since 2 is alone without any variables

4 0
2 years ago
Complete the tasks to subtract the polynomials
Talja [164]

Answer:

The additive inverse of the polynomial  being subtracted is -0.612-8+181

Step-by-step explanation:

Given expression : (1.32 +0.412 – 241) – (0.612 + 8 - 181)

Now the polynomial being subtracted : (0.612 + 8 - 181)

Additive inverse : The number in the set of real numbers that when added to a given number will give zero.

So, Additive inverse of 0.612 = -0.612

Additive inverse of 8 = -8

Additive inverse of -181 = 181

So, The additive inverse of polynomial being subtracted : -0.612-8+181

So, Option B is true

Hence the additive inverse of the polynomial  being subtracted is -0.612-8+181

5 0
3 years ago
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