Select all input values for which f(x) = 1
1 answer:
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Answer:
Only the point (-4, 22) is ON THE GRAPH of the equation. Please also check the attached graph.
Step-by-step explanation:
Given the equation
Let us substitute all the given points to check which points satisfy the equation.
Substitute (-4, -10) in the equation
As the R.H.S ≠ L.H.S, hence (-4, -10) does not satisfy the equation.
Hence, (-4, -10) is NOT ON THE GRAPH of the equation
Substitute (-4, 22) in the equation
As the R.H.S = L.H.S, hence (-4, 22) satisfies the equation.
Hence, (-4, 22) is ON THE GRAPH of the equation. Please also check the attached graph.
Substitute (1, -10) in the equation
As the R.H.S ≠ L.H.S, hence (1, -10) does not satisfy the equation.
Hence, (1, -10) is NOT ON THE GRAPH of the equation
Substitute (1, -2) in the equation
-2 = -4(1)+6
-2 = -4 + 6
-2 = 2
As the R.H.S ≠ L.H.S, hence (1, -2) does not satisfy the equation.
Hence, (1, -2) is NOT ON THE GRAPH of the equation
Therefore, from the above analysis, we conclude that only the point (-4, 22) is ON THE GRAPH of the equation. Please also check the attached graph.
