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3 years ago

What is the equation of a line passing through (-3,7) and having a slope of -1/5 PLEASE HELP

Mathematics

1 answer:

OLEGan [10]3 years ago

8 0

Answer:

y = -1/5x +32/5

Step-by-step explanation:

The slope intercept form of the equation of a line is

y = mx+b

we know m = -1/5

y = -1/5x+b

We know a x and y on the line

7 = -1/5(-3) +b

7 = 3/5 +b

Subtract 3/5 from each side

35/5 -3/5 = b

32/5 =b

So the equation is

y = -1/5x +32/5

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The simple interest on a loan of $6000 for 3 years was $900. What was the rate of interest per annum

Thepotemich [5.8K]

Answer:

Step-by-step explanation:

900/3=300

300/6000=0.05

0.05=5%

7 0

3 years ago

An auto maker estimates that the mean gas mileage of its sports utility vehicle is at least 20 miles per gallon. A random sample

Nady [450]

Answer:

Yes, we reject the auto maker's claim.

Step-by-step explanation:

H0 : μ ≥ 20

H1 : μ < 20

Sample mean, xbar = 18 ;

Sample size, n = 36

Standard deviation, s = 5

At α = 0.01

The test statistic :

(xbar - μ) ÷ s /sqrt(n)

(18 - 20) ÷ 5/sqrt(36)

-2 /0.8333333

= - 2.4

Pvalue from test statistic : Pvalue = 0.00819

Pvalue < α

0.00819 < 0.01

Hence, we reject the Null

7 0

3 years ago

??!?!?!?!?!!?!?!?!!?!!!?!!!!?

Nikitich [7]

Answer:

The third option, a rational number

like 1/5 + 2.5 is still rational (but neither irrational nor whole/an integer)

it would be 0.2 + 2.5 = 2.7 btw

1/5 + 5/2

= 2/10 + 25/10

= 27/10

6 0

3 years ago

A random sample of museum visitors were asked whether they will purchase tickets to an upcoming exhibit. The resulting confidenc

Vladimir [108]

Answer:

the margin of error is 0.05

Step-by-step explanation:

Margin of error = confidence interval ÷ 2

MOE = CI ÷ 2

Confidence interval CI = 0.2 - 0.1 = 0.1

MOE = CI ÷ 2 = 0.1 ÷ 2 = 0.05

the margin of error is 0.05

3 0

3 years ago

Find the exact value of tan (arcsin (two fifths)). For full credit, explain your reasoning.

Hitman42 [59]

$\bf sin^{-1}(some\ value)=\theta \impliedby \textit{this simply means}
\\\\\\
sin(\theta )=some\ value\qquad \textit{now, also bear in mind that}
\\\\\\
sin(\theta)=\cfrac{opposite}{hypotenuse}\qquad 
\qquad 
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}\\\\
-------------------------------\\\\$

$\bf sin^{-1}\left( \frac{2}{5} \right)=\theta \impliedby \textit{this simply means that}
\\\\\\
sin(\theta )=\cfrac{2}{5}\cfrac{\leftarrow opposite}{\leftarrow hypotenuse}\qquad \textit{now let's find the adjacent side}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}$

$\bf \pm \sqrt{5^2-2^2}=a\implies \pm\sqrt{21}=a
\\\\\\
\textit{we don't know if it's +/-, so we'll assume is the + one}\quad \sqrt{21}=a\\\\
-------------------------------\\\\
tan(\theta)=\cfrac{opposite}{adjacent}\qquad \qquad tan(\theta)=\cfrac{2}{\sqrt{21}}
\\\\\\
\textit{and now, let's rationalize the denominator}
\\\\\\
\cfrac{2}{\sqrt{21}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies \cfrac{2\sqrt{21}}{(\sqrt{21})^2}\implies \cfrac{2\sqrt{21}}{21}
$

7 0

3 years ago