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sergij07 [2.7K]
3 years ago
9

A large company that must hire a new president prepares a final list of five candidates,all of whom are equally qualified. Two o

f these candidates are members of a minority group.To avoid bias in the selection of the candidate, the company decides to select the presidentby lottery.the probability one of the minority candidates is hired we just need to divide the number of favorable outcomes 2 by the number of possibilities 5 and then we will have 0.4 but my questions isWhich concept of probability did you use to make this estimate?
Mathematics
1 answer:
nikitadnepr [17]3 years ago
5 0

Answer:

The estimate has been made using classical probability.

Step-by-step explanation:

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Is 2/4 equivalent to 1/4
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no no no no no no no no no no no

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3 years ago
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Use any method to solve the system of equations.<br> 3x + 4y = 12<br> 2x + 3y = 10<br> Solve for y.
Scilla [17]
(x , y) = (-4 , 6) There you go
7 0
3 years ago
A company that produces fine crystal knows from experience that 17% of its goblets have cosmetic flaws and must be classified as
Alex73 [517]

Answer:

0.3891 = 38.91% probability that only one is a second

Step-by-step explanation:

For each globet, there are only two possible outcoes. Either they have cosmetic flaws, or they do not. The probability of a goblet having a cosmetic flaw is independent of other globets. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

17% of its goblets have cosmetic flaws and must be classified as "seconds."

This means that p = 0.17

Among seven randomly selected goblets, how likely is it that only one is a second

This is P(X = 1) when n = 7. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{7,1}.(0.17)^{1}.(0.83)^{6} = 0.3891

0.3891 = 38.91% probability that only one is a second

7 0
3 years ago
Perform the indicated operation (-2i+3i)+(-1-4i)
Shtirlitz [24]

Answer:

  -1 -3i

Step-by-step explanation:

It is unusual to have two imaginary terms grouped together like this. Taking the question at face value, we treat i as though it were a variable, and collect terms in the usual way.

  (-2i +3i) +(-1 -4i) = i(-2+3-4) -1 = -1 -3i

4 0
3 years ago
10
Novay_Z [31]

Answer:

The sequence of transformations that maps ΔABC to ΔA'B'C' is the reflection across the <u>line y = x</u> and a translation <u>10 units right and 4 units up</u>, equivalent to T₍₁₀, ₄₎

Step-by-step explanation:

For a reflection across the line y = -x, we have, (x, y) → (y, x)

Therefore, the point of the preimage A(-6, 2) before the reflection, becomes the point A''(2, -6) after the reflection across the line y = -x

The translation from the point A''(2, -6) to the point A'(12, -2) is T(10, 4)

Given that rotation and translation transformations are rigid transformations, the transformations that maps point A to A' will also map points B and C to points B' and C'

Therefore, a sequence of transformation maps ΔABC to ΔA'B'C'. The sequence of transformations that maps ΔABC to ΔA'B'C' is the reflection across the line y = x and a translation 10 units right and 4 units up, which is T₍₁₀, ₄₎

5 0
3 years ago
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