Question

Sali throws an ordinary fair 6-sided dice once.

Answer 1

Answer:

$a=p=\frac{1}{6}\\\\b. \ p=\frac{1}{12}\\\\c.\ 1H,1T,2H,2T,3H,3T,4H,4T,5H,5T,6H,6T$

Step-by-step explanation:

a. A fair dice has 6 sides with unique identities.

-The sample space of one throw is 6 and each face has an equal chance of showing up.

-The probability of a 6 is calculated as:

$p(six)=\frac{1}{6}\\\\or \ =0.1667$

Hence, the probability of a 6 is $\frac{1}{6}$

b.A fair die has  6 unique faces.

-Two throws will have a sample space of 12.

-Each face has an equal probability of appearing twice.

-The probability of a 6 on both throws is:

$P(six)=2\times \frac{1}{6}\\\\=\frac{1}{12}$

c. A coin has 2 sides(head, tail) and a die has 6 sides.

-The total sample space for the simultaneous throw of a coin and die is 12.

-The resultant sample space is :

$1H,1T,2H,2T,3H,3T,4H,4T,5H,5T,6H,6T$