What is the mean for the data set?

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Eduardwww [97]

63 is your answer :)

8 0

2 years ago

*The rectangle to the left is divided into 12 shapes. One of them is a rectangle labeled with #1 and the remaining 11 shapes are

Mandarinka [93]

Given that the length of side of shaded area is 1 ft.

Making equal square of size of shaded area we have:

Horizontally number of shaded area are 12

Vertically number of shaded area are 11

So, the horizontal length of big rectangle is 12 ft.

The vertical length of big rectangle is 11 ft.

Area of big rectangle is 12*11

Area of given rectangle is 132 sq.ft.

6 0

3 years ago

Help please quickly!!!!!!1

IgorLugansk [536]

Answer:

$9$

Step-by-step explanation:

As per the problem, the given triangle is a right triangle. This is signified by the box around one of its angles, this box states that the angle it is surrounding is a right angle.

Since it is a right triangle, one can use the Pythagorean theorem to solve this problem. The Pythagorean theorem states that; ( $a^2 + b^2 = c^2$ ), where ( $a$ ) and ( $b$ ) are the legs of the right triangle, or the sides adjacent to the right angle. ( $c$ ) is the hypotenuse or the side opposite the right angle.

Substitute in the given values and solve, note that ( $a$ ) represents the unknown leg (side).

$a^2 + b^2 = c^2\\\\a^2 + (\sqrt{19})^2 = (100)^2\\\\a^2 + 19 = 100$

Inverse operations,

$a^2 + 19 = 100\\-19\\\\a^2 = 81\\\\a = \sqrt{81}\\\\a = 9$

8 0

3 years ago

Me pueden resolver estos ejercicios porfa

Misha Larkins [42]

Answer:

Bluhiii2i2i2iwuiijju8

8 0

2 years ago

Suppose a local manufacturing company claims their production line has a variance of less than 9.0. A quality control engineer d

Alexxx [7]

Answer:

$\chi^2 =\frac{35-1}{9} 2.12^2 =16.979$

$p_v =P(\chi^2$

If we compare the p value and the significance level provided we see that $p_v$ so on this case we have enough evidence in order to reject the null hypothesis at the significance level provided. And that means that the population variance is significantly lower than 9

Step-by-step explanation:

Notation and previous concepts

A chi-square test is "used to test if the variance of a population is equal to a specified value. This test can be either a two-sided test or a one-sided test. The two-sided version tests against the alternative that the true variance is either less than or greater than the specified value"

$n=35$ represent the sample size

$\alpha=0.01$ represent the confidence level

$s =2.12$ represent the sample deviation obtained

$\sigma_0 =3$ represent the value that we want to test

Null and alternative hypothesis

On this case we want to check if the population variance specification is lower than 9 and the deviation lower than 3, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 \geq 9$

Alternative hypothesis: $\sigma^2$

Calculate the statistic

For this test we can use the following statistic:

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

And this statistic is distributed chi square with n-1 degrees of freedom. We have eveything to replace.

$\chi^2 =\frac{35-1}{9} 2.12^2 =16.979$

Calculate the p value

In order to calculate the p value we need to have in count the degrees of freedom , on this case df= n-1= 35-1=34. And since is a left tailed test the p value would be given by:

$p_v =P(\chi^2$

In order to find the p value we can use the following code in excel:

"=CHISQ.DIST(16.979,34,TRUE)"

Conclusion

If we compare the p value and the significance level provided we see that $p_v$ so on this case we have enough evidence in order to reject the null hypothesis at the significance level provided. And that means that the population variance is significantly lower than 9

6 0

3 years ago