- The null and alternative hypotheses would be given by H₀: μ = 7 and H₀: μ ≠ 7.
- The test statistic is equal to 1.198.
- The p-value is equal to 0.1262.
- In conclusion, yes the mean discharge differs from 7 fluid ounces.
<h3>What is a null hypothesis?</h3>
A null hypothesis (H₀) can be defined the opposite of an alternate hypothesis (H₁) and it asserts that two (2) possibilities are the same.
<h3>How to calculate value of the test statistic?</h3>
The test statistic can be calculated by using this formula:
![t=\frac{x\;-\;u}{\frac{\delta}{\sqrt{n} } }](https://tex.z-dn.net/?f=t%3D%5Cfrac%7Bx%5C%3B-%5C%3Bu%7D%7B%5Cfrac%7B%5Cdelta%7D%7B%5Csqrt%7Bn%7D%20%7D%20%7D)
Where:
- is the standard deviation.
- n is the number of hours.
For this clinical trial (study), we should use a t-test and the null and alternative hypotheses would be given by:
H₀: μ = 7
H₀: μ ≠ 7
Next, we would calculate the t-test as follows:
![t=\frac{7.08\;-\;7}{\frac{0.25}{\sqrt{14} } }\\\\t=\frac{0.08}{\frac{0.25}{3.7417 } }](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B7.08%5C%3B-%5C%3B7%7D%7B%5Cfrac%7B0.25%7D%7B%5Csqrt%7B14%7D%20%7D%20%7D%5C%5C%5C%5Ct%3D%5Cfrac%7B0.08%7D%7B%5Cfrac%7B0.25%7D%7B3.7417%20%7D%20%7D)
t = 0.08/0.0668
t = 1.198.
For the p-value, we have:
P-value = P(t < 1.198)
P-value = 0.1262.
Therefore, the p-value (0.1262) is greater than α = 0.10. Based on this, we should fail to reject the null hypothesis.
In conclusion, yes the mean discharge differs from 7 fluid ounces.
Read more on null hypothesis here: brainly.com/question/14913351
#SPJ1
Answer:
-1/8
Step-by-step explanation:
MATH
Answer:
$0.56
Step-by-step explanation:
She bought 1,5 poumds for $0.84
if we multiply the price by 2/3 we will find how much it would cost for one pound
2/3 × 0.84 = $0.56
Answer: 9x
Step-by-step explanation:
Answer:
exponential form of ( 2^5 )^3 = 2^15
hence, the answer is ,
![2 {}^{15}](https://tex.z-dn.net/?f=2%20%7B%7D%5E%7B15%7D%20)