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Lera25 [3.4K]
3 years ago
11

Jill's bowling scores are approximately normally distributed with mean 170 and standard deviation 25, while jack's scores are ap

proximately normally distributed with mean 160 and standard deviation 10. if jack and jill each bowl one game, then assuming their scores are independent random variables, find the probability that
Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
5 0
Jill's bowling scores<span> are </span>approximately normally distributed<span> with </span>mean 170<span> and </span>standard deviation<span> 20,</span>while Jack's scores<span> are ... </span>If Jack<span> and </span>Jill each bowl one game<span>, </span>then assuming<span> that </span>their scores<span> are ... The difference of </span>means<span> of </span>Jack<span> and </span>Jill<span> follows a </span>normal distribution<span> with </span>mean<span> -</span>10<span> and </span>standard deviation<span> is: </span>25<span>.</span>
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Answer:

In the explanation

Step-by-step explanation:

x = 0, y = -2*0+11=11

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Hope this helps!

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What are reasons A and B in the proof?
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Lera25 [3.4K]

Answer:

105

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A=lw   A=(.5)πr²

to get the area of the shaded parts you have to subtract the area of the semicircle from the area of the rectangle

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A=144

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