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Lera25 [3.4K]
3 years ago
11

Jill's bowling scores are approximately normally distributed with mean 170 and standard deviation 25, while jack's scores are ap

proximately normally distributed with mean 160 and standard deviation 10. if jack and jill each bowl one game, then assuming their scores are independent random variables, find the probability that
Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
5 0
Jill's bowling scores<span> are </span>approximately normally distributed<span> with </span>mean 170<span> and </span>standard deviation<span> 20,</span>while Jack's scores<span> are ... </span>If Jack<span> and </span>Jill each bowl one game<span>, </span>then assuming<span> that </span>their scores<span> are ... The difference of </span>means<span> of </span>Jack<span> and </span>Jill<span> follows a </span>normal distribution<span> with </span>mean<span> -</span>10<span> and </span>standard deviation<span> is: </span>25<span>.</span>
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Write the equation for a line perpendicular to a line passing through points (-1,2) and (1,-8)
soldi70 [24.7K]

Answer:

Step-by-step explanation:

Slope m = (-8-2)/(1+1)=-10/2 = -5

Perpendicular slope-1/m = -1/-5 = 1/5

Equation of a line with perpendicular slope is

y-y1=(-1/m)(x-x1)

y - 2 = (1/5)(x+1)

y =2 +(1/5)(x+1)

3 0
3 years ago
I need help understanding this and help with the problems...
Pavel [41]

1. 15+37=?

  • 15=10+5 (given on the diagram)
  • 37=30+7 (given on the diagram)
  • add digits to digits 5+7=12=10+2
  • add tens to tens 10+30+10=50
  • add tens and digits 50+2=52.

2. 22+49=?

  • 22=20+2 (given on the diagram)
  • 49=40+9 (given on the diagram)
  • add digits to digits 2+9=11=10+1
  • add tens to tens 20+40+10=70
  • add tens and digits 70+1=71.

3. 38+26=?

  • 38=30+8 (given on the diagram)
  • 26=20+6 (given on the diagram)
  • add digits to digits 8+6=14=10+4
  • add tens to tens 30+20+10=60
  • add tens and digits 60+4=64.

Answer: 1) 52; 2) 71; 3) 64.

7 0
3 years ago
Read 2 more answers
Which of the following tables shows the correct steps to transform x^2+8x+15=0 into the form of (x-p)^2=q (p and q are integers)
Montano1993 [528]
<span>The best and most correct answer among the choices provided by the question is the third choice:
table 3:
step 1.x^2+8x+15+1=0+1
step 2.x^2+8x+16=1
<span>step 3.(x+4)^2=1</span>

I hope my answer has come to your help. God bless and have a nice day ahead!</span>
8 0
3 years ago
Read 2 more answers
I need it ASAP, Questions are attached as a photo
ELEN [110]

Answer:

8- 26 cm

7- 85 cm^2

1-23 cm

5 0
2 years ago
Applications 24. A rocket is launched into the air. Its height in feet, after x seconds, is given by the equation The starting h
SVEN [57.7K]

The given function is

h(x)=-16x^2+300x+20

According to this function, the starting height of the rocket is 20 feet because that's the initial condition of the problem stated by the independent term.

Additionally, we find the maximum height by calculating the vertex of the function V(h,k).

h=-\frac{b}{2a}

Where a = -16 and b = 300.

\begin{gathered} h=-\frac{300}{2(-16)}=\frac{300}{32}=\frac{150}{16}=\frac{75}{8} \\ h=9.375 \end{gathered}

Then, we find k by evaluating the function

\begin{gathered} k=-16(9.375)^2+300(9.375)+20 \\ k=-1406.25+2812.5+20=1426.25 \end{gathered}

Hence, the maximum height is 1426.25 feet.

At last, to know the time need to hit the ground, we just use h=9.375 and we multiply it by 2

t=2\cdot9.375=18.75

Hence, the rocket hits the ground after 18.75 seconds.

6 0
1 year ago
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