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Lera25 [3.4K]
2 years ago
11

Jill's bowling scores are approximately normally distributed with mean 170 and standard deviation 25, while jack's scores are ap

proximately normally distributed with mean 160 and standard deviation 10. if jack and jill each bowl one game, then assuming their scores are independent random variables, find the probability that
Mathematics
1 answer:
olya-2409 [2.1K]2 years ago
5 0
Jill's bowling scores<span> are </span>approximately normally distributed<span> with </span>mean 170<span> and </span>standard deviation<span> 20,</span>while Jack's scores<span> are ... </span>If Jack<span> and </span>Jill each bowl one game<span>, </span>then assuming<span> that </span>their scores<span> are ... The difference of </span>means<span> of </span>Jack<span> and </span>Jill<span> follows a </span>normal distribution<span> with </span>mean<span> -</span>10<span> and </span>standard deviation<span> is: </span>25<span>.</span>
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2 years ago
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Karo-lina-s [1.5K]

Answer:

First one: yes

Second one: yes

Third one: no

Step-by-step explanation:

To find the midpoint of a line segment, you take the x and y coordinates of the 2 points, add each of them up, and divide each of them by 2.

First one: x = (1+3)/2 = 2, y = (2+4)/2 = 3, so it's correct.

Second one: x = (-1+3)/2 = 1, y = (1+-1)/2 = 0, so it's correct.

Third one: x = (-3+-1)/2 = -2, y = (0+5)/2 ≠ 2, so it's not correct.

I really hope this helped.

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3 years ago
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2 years ago
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Marat540 [252]

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