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Oksanka [162]
3 years ago
15

Can someone help me with 8 please

Mathematics
1 answer:
Dmitry [639]3 years ago
4 0

Answer:

96,144,192,240,288

Step-by-step explanation:

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What is the area of the poster board that she has left
steposvetlana [31]
Find the area of the parallelogram, find the area of the triangle, then subtract the triangle's area from the area of the parallelogram.

Area of Parallelogram:
A= base * height
A= 20 in * 10 in
A= 200 in^2

Area of Triangle:
A= 1/2 base * height
A= 1/2 (10 in)(9 in)
A= 1/2 (90)
A= 45 in ^2

Area of Poster Left:
subtract the difference
A= Parallelogram Area - Triangle Area
A= 200 in^2 - 45 in^2
A= 155 in^2

ANSWER: 155 in^2 is the area of the poster board she has left.

Hope this helps! :)
5 0
3 years ago
Expand 3(z+3) please help me solve this
mojhsa [17]

Answer:

3(z+3) = 3z + 9 if thats what your asking

Step-by-step explanation:

7 0
3 years ago
Whats the capacity of a water bottle thats 8 inches
suter [353]
1 pt; or 1 pint seems most reasonable here.

8 0
3 years ago
Help me plsssss!!!!!
Margarita [4]

Answer:

the

answer is x-8

hope it will help you

have a great day

6 0
2 years ago
Read 2 more answers
Pls help me not fail
nignag [31]

Answer:

D

Step-by-step explanation:

Using the Cosine rule to find AC

AC² = BC² + AB² - (2 × BC × AB × cosB )

      = 18² + 12² - ( 2 × 18 × 12 × cos75° )

      = 324 + 144 - 432cos75°

      = 468 - 111.8

      = 356.2 ( take the square root of both sides )

AC = \sqrt{356.2} ≈ 18.9

-----------------------------------------

Using the Sine rule to find ∠ A

\frac{18}{sinA} = \frac{18.9}{sin75} ( cross- multiply )

18.9 sinA = 18 sin75° ( divide both sides by 18.9 )

sinA = \frac{18sin75}{18.9} , then

∠ A = sin^{-1} ( \frac{18sin75}{18.9} ) ≈ 66.9°

4 0
3 years ago
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