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3 years ago

Write an equation in the form

Mathematics

1 answer:

elena-s [515]3 years ago

8 0

Answer:

y=4x+7

Slope m=4 with the equation y2-y1/x2-x1 with any points

y-intercept (0,7)

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Your computer password has 4 capital letters followed by 4 digits. Your

kodGreya [7K]

There are 26 letters, four times. There are 10 numbers, four times. 26x26x26x26=456,976
10x10x10x10= 10,000
Final Answer: 4,569,760,000

4 0

2 years ago

What is the constant term that completes the perfect square trinomial. y^2 + y

lara [203]

Y^2 + y

y^2 + y + 0.25 <=== the constant term is 0.25
(y + 0.5)(y + 0.5) =
(y + 0.5)^2

to find the constant, u take half of ur y coefficient (not the y^2 coefficient)....y^2 + 1y....ur y coefficient is 1......half of it is 0.5....u then square it....(0.5^2) = 0.25 ....this is ur constant

4 0

3 years ago

The function shown models the horizontal and vertical distances, in feet, traveled by a person on a roller coaster. What horizon

Pani-rosa [81]

Answer:

20 and 25

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

I don’t understand this help please

Elodia [21]

Answer:

Step-by-step explanation:

The first simplification we can make is to replace 6^0 with 1.

The first rules of exponents we can apply are ...

(a·b)^c = a^c·b^c . . . . . . similar to the distributive property

 (a^b)^c = a^(b·c)

This reduces your expression to ...

$(2^8\cdot 3^{-5})^{-2}\cdot\left(\dfrac{3^{-2}}{2^3}\right)^4\cdot 2^{28}=2^{8(-2)}\cdot 3^{-5(-2)}\cdot\dfrac{3^{-2(4)}}{2^{3(4)}}\cdot 2^{28}\\\\=2^{-16}\cdot 3^{10}\cdot\dfrac{3^{-8}}{2^{12}}\cdot 2^{28}$

Now we can apply another two rules of exponents:

 (a^b)(a^c) = a^(b+c)

 1/a^b = a^-b

Using these, we have ...

$=2^{-16-12+28}\cdot 3^{10-8}\\\\=2^0\cdot 3^2\\\\=1\cdot 9=9$

The value of the expression is 9.

3 0

3 years ago

1. Simplify the expression. 3[(11–6)2+5] A 5 B 3 C 15 D 6

kirill [66]

Answer:

3 is the answer

mutiply and open bracket minus each other

4 0

2 years ago