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nasty-shy [4]
3 years ago
5

Find the common ratio of the geometric sequence 9, -18, 36, ...

Mathematics
1 answer:
Anna35 [415]3 years ago
6 0

Answer:

-2

Step-by-step explanation:

Each term is being multiplied by -2.

9(-2) → -18

-18(-2) → 36

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1500 customers hold a VISA card; 500 hold an American Express card; and, 75 hold a VISA and an American Express. What is the pro
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Answer:

There is 15% probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

P(VISA \:| \:AE) = 15\%\\

Step-by-step explanation:

Number of customers having a Visa card = 1,500

Number of customers having an American Express card = 500

Number of customers having Visa and American Express card = 75

Total number of customers = 1,500 + 500 = 2,000

We are asked to find the probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

This problem is related to conditional probability which is given by

P(A \:| \:B) = \frac{P(A \:and \:B)}{P(B)}

For the given problem it becomes

P(VISA \:| \:AE) = \frac{P(VISA \:and \:AE)}{P(AE)}

The probability P(VISA and AE) is given by

P(VISA and AE) = 75/2000

P(VISA and AE) = 0.0375

The probability P(AE) is given by

P(AE) = 500/2000

P(AE) = 0.25

Finally,

P(VISA \:| \:AE) = \frac{P(VISA \:and \:AE)}{P(AE)}\\\\P(VISA \:| \:AE) = \frac{0.0375}{0.25}\\\\P(VISA \:| \:AE) = 0.15\\\\P(VISA \:| \:AE) = 15\%\\

Therefore, there is 15% probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

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serg [7]

Answer:

\large\boxed{3x^3+23x^2+63x+55}

Step-by-step explanation:

\text{Use FOIL:}\\\\(a+b)(c+d)=ac+ad+bc+bd

(3x+5)(x^2+6x+11)\\\\=(3x)(x^2)+(3x)(6x)+(3x)(11)+(5)(x^2)+(5)(6x)+(5)(11)\\\\=3x^3+18x^2+33x+5x^2+30x+55\qquad\text{combine like terms}\\\\=3x^3+(18x^2+5x^3)+(33x+30x)+55\\\\=3x^3+23x^2+63x+55

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