If you go with Blackburn, you have to pay 25 bucks right off, for the web services hosting setup, that's for them to add your account, and allocate resources on their end for you.
After that, for every passing month, you have to pay 5.69 bucks for the service they provide on daily basis.
if you with Randall, they also charge for setup fee, just cheaper, $6 at once, and then for every month is $9.49.
Blackburn for
1 month 5.69(1) + 25
2 months 5.69(2) + 25
3 months 5.69(3) + 25
x months 5.69(x) + 25, or 5.69x + 25
Randall for
1 month 9.49(1) + 6
2 months 9.49(2) + 6
3 months 9.49(3) + 6
x months 9.49(x) + 6, or 9.49x + 6
------------------------------------------------------------------------------------
y = 5.69x + 25
y = 9.49x + 6
Answer:
4.05% probability that a randomly selected adult has an IQ greater than 123.4.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

Probability that a randomly selected adult has an IQ greater than 123.4.
This is 1 subtracted by the pvalue of Z when X = 123.4. So



has a pvalue of 0.9595
1 - 0.9595 = 0.0405
4.05% probability that a randomly selected adult has an IQ greater than 123.4.
Step-by-step explanation:
6b x>=1
6c y>7
7a x>3
7b -2<=2x<6
-1<=x<3
answer:-1,0,1,2,3