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2 years ago

13.5-ounce bottle cost 2.19. A 29.2-ounce bottle costs 5.37 find the unit price for each size

Mathematics

1 answer:

maks197457 [2]2 years ago

6 0

Answer:

A)Unit prize is $0.162

B)Unit prize is $0.183

Step-by-step explanation:

A) 13.5-ounce bottle cost 2.19

Cost of 13.5 ounce bottle =2.19

Cost of 1 ounce bottle = $\frac{2.19}{13.5}=0.162$

So, Unit prize is $0.162

B)29.2-ounce bottle costs 5.37

Cost of 29.2 ounce bottle = 5.37

Cost of 1 ounce bottle = $\frac{5.37}{29.2}=0.183$

So, Unit prize is $0.183

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The healthy weight for the dog is around 64 lbs

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3 years ago

Which equation represents a function? A. y2 + x = 6 B. y4 + x3 = 3 C. y – x2 = 4 D. y2 – x2 = 7 E. y2 + x2 = 7

valentinak56 [21]

Answer:

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Step-by-step explanation:

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3 years ago

Perform the indicated operation 5(3x^3)^3-2(3x^3)

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5(3x^3)^3-2(3x^3)
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3 years ago

Choose the answer that validates that the rate of change is constant by showing that the ratios of the two quantities are propor

docker41 [41]

Given:

The table of values is

Number of Students : 7 14 21 28

Number of Textbooks : 35 70 105 140

To find:

The rate of change and showing that the ratios of the two quantities are proportional and equivalent to the unit rate.

Solution:

The ratio of number of textbooks to number of students are

$\dfrac{35}{7}=5$

$\dfrac{70}{14}=5$

$\dfrac{105}{21}=5$

$\dfrac{140}{28}=5$

All the ratios of the two quantities are proportional and equivalent to the unit rate.

Let y be the number of textbooks and x be the number of students, then

$\dfrac{y}{x}=k$

Here, k=5.

$\dfrac{y}{x}=5$

$y=5x$

Hence the rate of change is constant that is 5.

8 0

3 years ago

Help asap! 50 Points! 10 Questions!

tensa zangetsu [6.8K]

Part 1) If a cylinder has a surface area of 36 square inches and its radius is 1.6 inches, how tall is the cylinder in inches? π = 3.14. Round to the nearest tenth.

we know that
surface area of the cylinder=2*area of the base+perimeter of the base*height

area of the base==pi*r²*h-----> 3.14*1.6²*h----> 8.0384*h in²

perimeter of the base=2*pi*r---> 2*3.14*1.6----> 10.048 in

surface area=36 in²
so
36=2*[8.0384*h]+10.048*h----> 36=26.1248*h
h=36/26.1248----> h=1.38 in------> h=1.4 in

the answer Part 1) is
h=1.4 in

Part 2) 2. A regular hexagonal pyramid has a base area of 29 in^2 and a lateral area of 210 in^2. What is the surface area of the hexagonal pyramid?

surface area of the hexagonal pyramid=2*area of base+lateral area
surface area of the hexagonal pyramid=2*29+210----> 268 in²

the answer part 2) is
surface area=268 in²

Part 3) What is the surface area of the following cylinder in square inches? Use π = 3.14 and round your answer to the nearest tenth.
Radius = 3.2 Height = 4.1
we know that
surface area of the cylinder=2*area of the base+perimeter of the base*height

area of the base==pi*r²*h-----> 3.14*3.2²*4.1----> 131.83 in²

perimeter of the base=2*pi*r---> 2*3.14*3.2----> 20.096in

surface area=2*131.83+20.096*4.1------> 346.05 in²-----> 346.1 in²

the answer Part 3)
surface area=346.1 in²

part 4)A cube has surface area of 150 in^2. How long is each side of the cube?

we know that
surface area of cube=6*b²
where b is the length side of the cube
SA=6*b²------> b=√SA/6------> b=√150/6-----> √25----> b=5 in

the answer Part 4) is
b=5 in

Part 5) A cube has sides that are 3 in. long. What is the surface area of the cube?
we know that
surface area of cube=6*b²
where b is the length side of the cube
b=3 in
so
SA=6*3²----> 54 in²

the answer Part 5) is
SA=54 in²

Part 6) What is the surface area of this box?
Height = 3.5 Length = 6 width = 3

surface area of the box=2*area of the base+perimeter of base*height

area of the base=6*3----> 18 ft²

perimeter of the base=2*[6+3]----> 18 ft
height=3.5 ft

surface area of the box=2*18+18*3.5----> 99 ft²

the answer Part 6) is
SA=99 ft²

Part 7) If a cylinder has a surface area of 59 square inches and its radius is 2.1 inches, how tall is the cylinder in inches? Use π = 3.14. Round to the nearest tenth


we know that
surface area of the cylinder=2*area of the base+perimeter of the base*height

area of the base==pi*r²*h-----> 3.14*2.1²*h----> 13.8474*h in²

perimeter of the base=2*pi*r---> 2*3.14*2.1----> 13.188 in

surface area=59 in²
so
59=2*[13.8474*h]+13.188*h----> 59=40.8828*h
h=59/40.8828----> h=1.44 in------> h=1.4 in

the answer Part 7) is
h=1.4 in

Part 8) What is the surface area of the cone below, rounded to the nearest tenth? Use π = 3.14.
Height = 12 Radius = 5
surface area of the cone=pi*r²+pi*r*l
r=5 in
h=12 in
l=slant height
l²=r²+h²----> l²=5²+12²----> l²=169-----> l=13 in

surface area of the cone=3.14*5²+3.14*5*13-----> 282.6 in²

the answer Part 8) is
SA=282.6 in²

Part 9) A square pyramid has a surface area of 202 ft^2 and a base area of 53 ft^2. What is the lateral area of the pyramid?

we know that
surface area=area of the base+lateral area
lateral area=surface area-area of the base
lateral area=202-53----> 149 ft²

the answer Part 9) is
LA=149 ft²

Part 10)What is the surface area of the cone below, rounded to the nearest tenth? Use π = 3.14
Radius = 2 Height = 4

surface area of the cone=pi*r²+pi*r*l
r=2 cm
h=4 cm
l=slant height
l²=r²+h²----> l²=2²+4²----> l²=20-----> l=4.47 cm

surface area of the cone=3.14*2²+3.14*2*4.47-----> 40.63 cm²

the answer Part 10) is
SA=40.6 cm²

3 0

3 years ago