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OLEGan [10]
4 years ago
5

The table below shows 10 data values:

Mathematics
1 answer:
bulgar [2K]4 years ago
7 0

Answer:

The answer is the second option

Minimum = 203, Q1 =217, median = 230, Q3 = 245, maximum = 290

Step-by-step explanation:

First order the data from lowest to highest

203, 216, 217, 224, 224, 236, 245, 245 ,262 ,290

Minimun = 203

Maximum =290

Now divide the data in half

203, 216, 217, 224, 224,            236, 245, 245 ,262 ,290

Divide half of the first half of the data. The data of the medium is the first quartile

1) 203, 216, [217], 224, 224

                      Q1

Divide half of the second half of the data. The data of the medium is the third quartile

2)  236, 245, [245] ,262 ,290

                         Q3

The average between the two values that are in the center of the 10 ordered data is the median

203, 216, 217, 224,  [224, 236], 245, 245 ,262 ,290

Median =\frac{224+236}{2}=230

Median=230

The answer is the second option

Minimum = 203, Q1 =217, median = 230, Q3 = 245, maximum = 290

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