Answer:
Giorgio
Step-by-step explanation:
Answer:
<u>B. There is sufficient evidence that the mean of the pressure required to open a certain valve has changed. </u>
Step-by-step explanation:
We make this conclusion based on these reasons:
- We are told that the "null hypothesis was rejected" after the <em>"manager feels that the pressure variability has changed.,</em> meaning the <u>null hypothesis was the opposite of what occurred; that is to say, it is the alternate hypothesis that proved true instead.</u>
- <em>"changes in the manufacturing process"</em> form what can be called "sufficient evidence" that the mean of the pressure required to open the valve has changed, thereby going against the null hypothesis.
It is based on the above reasons that the null hypothesis was rejected.
Answer:
q = 2/3p - 3
Step by step:
2q+2p = 1+5q
2q - 5q = -2p + 1
-3q = -2p + 1
q = 2/3p - 3
Answer: 30 should be negative
Step-by-step explanation:
when having an equation like that, you must multiply -5 by 3, which equals to -15, then multiply-5 by 6 which then equals to -30. The correct equation should be -5(3+6)= -15+-30= -45
I think this should be correct, hope this helps!
Answer:
$4
Step-by-step explanation:
The two purchases can be written in terms of the cost of an adult ticket (a) and the cost of a student ticket (s):
7a +16s = 120 . . . . . . . . price for the first purchase
13a +9s = 140 . . . . . . . . price for the second purchase
Using Cramer's rule, the value of s can be found as ...
s = (120·13 -140·7)/(16·13 -9·7) = 580/145 = 4
The cost of a student ticket is $4.
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<em>Comment on Cramer's Rule</em>
Cramer's rule is particularly useful for systems that don't have "nice" numbers that would make substitution or elimination easy methods to use. If you locate the numbers in the equation, you can see the X-patterns that are used to compute the numerator and denominator differences.
The value of a is (16·140 -9·120)/(same denominator) = 1160/145 = 8. I wanted to show you these numbers so you could see the numerator X-pattern for the first variable.
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Of course, graphical methods can be quick and easy, too.
