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3 years ago

Order from least to greatest: -0.45 -25 |-50| 7.3 -1.3

Mathematics

1 answer:

Scorpion4ik [409]3 years ago

5 0

Answer:

-25,-1.3, -0.45, 7.3, I-50I

Step-by-step explanation:

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The sum of two twin primes is 60. What are the numbers

Fudgin [204]

Its 29 and 31. thats the answer

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3 years ago

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What is equation is equivalent to 6(3p-2)=20?

Simora [160]

Answer:

$p=\frac{16}{9}$

Step-by-step explanation:

$6(3p-2)=20$

Distribute the brackets.

$6(3p)+6(-2)=20$

$18p-12=20$

Add $12$ on both sides.

$18p-12+12=20+12$

$18p=20+12$

$18p=32$

Divide $18$ on both sides.

$\frac{18p}{18}=\frac{32}{18}$

$p=\frac{16}{9}$

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2 years ago

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If f(x) = 3x + 12, find the value of x so that f(x) = 36.

Fynjy0 [20]

Answer:

The answer is 8 .

Step-by-step explanation:

f(x)=36

36=3x+12

36-12 and 12 -12

36-12=24

24 divided by the 3 that left in the equation equals 8 .

36=3x+12

-12 -12

24=3x

divided 24 by 3 and get 8

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3 years ago

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How many grams are 7.00 x 1022 molecules of NaOH?

olya-2409 [2.1K]

Answer:

46.5

explanation

6.022*10^23 molecules=40g.

7.00*10^23=40*7.00*10^23/6.022*10^23 g =46.5 g

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3 years ago

Factor the polynomial, x2 + 5x + 6

patriot [66]

Answer:

Choice b.

$x^{2} + 5\, x + 6 = (x + 3)\, (x + 2)$ .

Step-by-step explanation:

The highest power of the variable $x$ in this polynomial is $2$ . In other words, this polynomial is quadratic.

It is thus possible to apply the quadratic formula to find the "roots" of this polynomial. (A root of a polynomial is a value of the variable that would set the polynomial to $0$ .)

After finding these roots, it would be possible to factorize this polynomial using the Factor Theorem.

Apply the quadratic formula to find the two roots that would set this quadratic polynomial to $0$ . The discriminant of this polynomial is $(5^{2} - 4 \times 1 \times 6) = 1$ .

$\begin{aligned}x_{1} &= \frac{-5 + \sqrt{1}}{2\times 1} \\ &= \frac{-5 + 1}{2} \\ &= -2\end{aligned}$ .

Similarly:

$\begin{aligned}x_{2} &= \frac{-5 - \sqrt{1}}{2\times 1} \\ &= \frac{-5 - 1}{2} \\ &= -3\end{aligned}$ .

By the Factor Theorem, if $x = x_{0}$ is a root of a polynomial, then $(x - x_0)$ would be a factor of that polynomial. Note the minus sign between $x$ and $x_{0}$ .

The root $x = -2$ corresponds to the factor $(x - (-2))$ , which simplifies to $(x + 2)$ .
The root $x = -3$ corresponds to the factor $(x - (-3))$ , which simplifies to $(x + 3)$ .

Verify that $(x + 2)\, (x + 3)$ indeed expands to the original polynomial:

$\begin{aligned}& (x + 2)\, (x + 3) \\ =\; & x^{2} + 2\, x + 3\, x + 6 \\ =\; & x^{2} + 5\, x + 6\end{aligned}$ .

4 0

2 years ago