A right triangle has a hypotenuse of length 6 ft and one leg of length 2 ft.
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I'm assuming the limit is supposed to be
Multiply the numerator by its conjugate, and do the same with the denominator:
so that in the limit, we have
Factorize the first term in the denominator as
The terms cancel, leaving you with
and the limand is continuous at , so we can substitute it to find the limit has a value of -1/18.
Answer:hope this helps.. please mark as brainliest.....
