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andrew-mc [135]
3 years ago
6

Please answer!!!! will make brainliest!!!

Mathematics
1 answer:
hammer [34]3 years ago
7 0

Answer:

B

Step-by-step explanation:

1.

  • 3(x+3) - 2 < 4
  • 3x + 9 -2 < 4
  • 3x < 4-7
  • 3x < - 3
  • x < -1
  • x = (-oo, -1)

2.

  • 1 - x ≤ -1
  • - x ≤ -1 - 1
  • -x ≤ -2
  • x ≥ 2
  • x = [2, +oo)

Correct choice is B.

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Minimum value: -3* \sqrt{n}

Step-by-step explanation:

Let g(x) = x_1^2 + x_2^2+x_3^2+ ----+ x_n^2 , the restriction function.The Lagrange Multiplier problem states that an extreme (x1, ..., xn) of f with the constraint g(x) = 9 has to follow the following rule:

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Where c is a constant that doesnt depend on i. In other words, there exists c such that (x1, x2, ..., xn) = (c,c, ..., c). Now, since g(x1, ..., xn) = 9, we have that n * c² = 9, or

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On the other hand, when c is negative, f reaches a minimum, -3 * \sqrt{n}

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