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2 years ago

In rectangle KLMN, KM = 10x + 24 and LN = 64. Find the value of x.

Mathematics

1 answer:

Mice21 [21]2 years ago

5 0

_________X=30____
_________-________

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At a football stadium, 20% of the fans in attendance were teenagers. If there were 180

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The answer is 900 people.

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2 years ago

Describe two different strategies you could us to add 16+35+24+14

olga nikolaevna [1]

1. You could add 16 + 35 (which equals 51), then add 51 + 24 (equals 75) then add 14 (equals 89)
2. Add 16 + 35 (equals 51), add 24 + 14 (equals 38) then add 51+38 (Equals 89)

5 0

2 years ago

Can someone help me with one pleaseT (ToT)

uysha [10]

Answer:

Add 1 to both sides.

Multiply both sides by -2.

Add 8 to both sides.

Divide both sides by 5.

Step-by-step explanation:

Step 1

$-\dfrac{1}{2}(5x-8)-1=6\quad \quad \textsf{Write the equation.}$

Step 2

$-\dfrac{1}{2}(5x-8)=7 \quad \quad \textsf{Add 1 to both sides.}$

This is called the Addition Property of Equality. When the same number is added to both sides of an equation, the two sides remain equal.

$\implies -\dfrac{1}{2}(5x-8)-1+1=6+1$

$\implies -\dfrac{1}{2}(5x-8)=7$

Step 3

$5x-8=-14 \quad \quad \textsf{Multiply both sides by -2.}$

This is called the Multiplication Property of Equality. When both sides of an equation are multiplied by the same number, the two sides remain equal.

$\implies -2 \cdot -\dfrac{1}{2}(5x-8)=-2 \cdot 7$

$\implies 5x-8=-14$

Step 4

$5x=-6 \quad \quad \textsf{Add 8 to both sides.}$

This is called the Addition Property of Equality. When the same number is added to both sides of an equation, the two sides remain equal.

$\implies 5x-8+8=-14+8$

$\implies 5x=-6$

Step 5

$x=-\dfrac{6}{5} \quad \quad \textsf{Divide both sides by 5.}$

This is called the Division Property of Equality. When both sides of an equation are divided by the same number, the two sides remain equal.

$\implies \dfrac{5x}{5}=\dfrac{-6}{5}$

$\implies x=\dfrac{-6}{5}$

Conclusion

$\begin{aligned}-\dfrac{1}{2}(5x-8)-1 & =6 & \quad \quad& \textsf{Write the equation.}\\\\-\dfrac{1}{2}(5x-8) & =7 & & \boxed{\textsf{Add 1 to both sides.}}\\\\5x-8 & =-14 & & \boxed{\textsf{Multiply both sides by -2.}}\\\\5x & =-6 & & \boxed{\textsf{Add 8 to both sides.}}\\\\x & =-\dfrac{6}{5} & & \boxed{\textsf{Divide both sides by 5.}}\\\end{aligned}$