Using the law os cosines formula b^2 = a^2 + c^2 - 2*a*c*cos(B)
a = 17, b = 8, c = 16
8^2 = 17^2 + 16^2 - 2*17*16* cos(B)
64 = 289 + 256 - 544 * cos(B)
544*cos(B) = 289 + 256 - 64
544 * cos(B) = 481
cos (B) = 481/544
B = arccos(481/544)
B = 27.8 degrees
Step-by-step explanation:
You're asking why
let's transpose the first equation for y
-2x-6y=18
-6y=18+2x
6y=-18-2x
y=-18/6-2x/6
y=-3-⅓x as required
Since there are 3 odd numbers ( 1, 3 and 5) and 3 even numbers ( 2, 4 and 6) in the cube ,
The chance of getting an odd number is 50/50 or 50%
So out of 1000 she will probably get 500 odd since 1000 × 0.5 (which is 50%) is 500
Put them all in to decimals so dived 1 by 5 and 32 by 100 then they will all be decimals and you can more essay compare them
Answer:
99
Step-by-step explanation:
You can solve it by Squaring/multiply 18 by itself and 15 by itself then subtract them both:
(18 × 18) - (15 × 15)
324 - 225
99
You could also do difference of two squares:
(x² - y²)
= (x + y) (x - y)
= (18 + 15) (18 - 15)
= (33) (3)
= 99
