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nordsb [41]
3 years ago
5

Which is equivalent to (4xy-3x)^2, and what type of special product is it?

Mathematics
2 answers:
mars1129 [50]3 years ago
8 0

It's not the difference of squares, rather it is the square of a difference. That leaves a perfect square trinomial, which narrows your selection to two choices. An expression with 2 terms is not a trinomial, so that further narrows your selection. The appropriate choice is

... (4xy -3z)² = 16x²y² -24xyz +9z², a perfect square trinomial

_____

The expression you have in your problem statement has no z term, so none of the choices is applicable to that one.

maria [59]3 years ago
5 0

Answer:

The correct option is 4.

Step-by-step explanation:

The given expression is

(4xy-3z)^2

Algebraic formula:

(a-b)^2=a^2-2ab+b^2

It is a perfect square trinomial.

Using algebraic formula, we get

(4xy-3z)^2=(4xy)^2-2(4xy)(3z)+(3z)^2

(4xy-3z)^2=16x^2y^2-24xyz+9z^2

Therefore option 4 is correct.

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Is the square root of 10 greater less than or equal to 5
Ierofanga [76]

Answer: it is less then 5

Step-by-step explanation:

Because 10 lies between two consecutive perfect squares (in increasing order) 10 is located between the square roots of these two numbers. This means that 10 is located between 10 is less than 5.

4 0
2 years ago
Read 2 more answers
Select the graph for the solution of the open sentence. Click until the correct graph appears. |x| &gt; 4
nadezda [96]

Answer:

***********o                                                         o**************

<----------(-4)--------(-2)--------(0)--------(-2)----------(4)-------------->

x>4 or x<-4

Step-by-step explanation:

You are looking for numbers that give you a distance, x, greater than 4 from 0. That wouldn't be anything between -4 and 4 because these would all give you a distance less than 4 from 0. So the answer would be to shade everything greater than 4 while also shading everything less than -4.

Here is a number line <-----|-----|-----|-----|-----|-----|-----|-----|-->

                                          -6    -4   -2    0     2     4    6    8

                                                 

Let's think about this more which of these numbers on this number line would satisfy |x|>4?

Numbers inside the numbers -4 and 4.

Or the numbers on the outside.

Let's try the inside numbers:

-2,02

|-2|>4

 2>4 is false which means -2 doesn't satisfy |x|>4

|0|>4

 0>4 is false which means 0 doesn't satisfy  |x|>4

|2|>4

 2>4 is false which means 2 doesn't satisfy  |x|>4

We could also try -4 and 4... but these will both give you a distance equal to 4 from 0.  And we are looking for greater than.

|-4|>4

 4>4 is false which mean -4 doesn't satisfy |x|>4

|4|>4

 4>4  is false which means 4 doesn't satisfy |x|>4

Now let's try the numbers on the outside:

-6,6,8

|-6|>4

 6>4 is true so -6 does satisfy |x|>4

|6|>4

 6>4 is true so 6 does satisfy |x|>4

|8|>4

 8>4 is true so 8 does satisfy |x|>4

So what I'm trying to do is convince you more that the only numbers that would satisfy |x|>4 are numbers outside the interval from -4 to 4.

So x>4 or x<-4.

On a number line the solution would look like this:

***********o                                                         o**************

<----------(-4)--------(-2)--------(0)--------(-2)----------(4)-------------->

We have holes at -4 and 4 to mean we do not include those numbers.  We would have if the inequality read |x| \ge 4.  The line underneath this inequality means to include or equals.  We do not want to include; we did not have the equal sign.   The only difference between the two solutions would be to fill the holes if you |x| \ge 4.

4 0
3 years ago
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