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nordsb [41]
3 years ago
5

Which is equivalent to (4xy-3x)^2, and what type of special product is it?

Mathematics
2 answers:
mars1129 [50]3 years ago
8 0

It's not the difference of squares, rather it is the square of a difference. That leaves a perfect square trinomial, which narrows your selection to two choices. An expression with 2 terms is not a trinomial, so that further narrows your selection. The appropriate choice is

... (4xy -3z)² = 16x²y² -24xyz +9z², a perfect square trinomial

_____

The expression you have in your problem statement has no z term, so none of the choices is applicable to that one.

maria [59]3 years ago
5 0

Answer:

The correct option is 4.

Step-by-step explanation:

The given expression is

(4xy-3z)^2

Algebraic formula:

(a-b)^2=a^2-2ab+b^2

It is a perfect square trinomial.

Using algebraic formula, we get

(4xy-3z)^2=(4xy)^2-2(4xy)(3z)+(3z)^2

(4xy-3z)^2=16x^2y^2-24xyz+9z^2

Therefore option 4 is correct.

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Suppose 12% of students are veterans. From a sample of 263 students, how unusual would it be to have less than 22 veterans?
kkurt [141]

Answer:

Yes, both np and n(1-p) are ≥ 10

Mean = 0.12 ; Standard deviation = 0.02004

Yes. There is a less than 5% chance of this happening by random variation. 0.034839

Step-by-step explanation:

Given that :

p = 12% = 0.12 ;

Sample size, n = 263

np = 263 * 0.12 = 31.56

n(1 - p) = 263(1 - 0.12) = 263 * 0.88 = 231.44

According to the central limit theorem, distribution of sample proportion approximately follow normal distribution with mean of p = 0.12 and standard deviation sqrt(p*(1 - p)/n) = sqrt (0.12 *0.88)/n = sqrt(0.0004015) = 0.02004

Z = (x - mean) / standard deviation

x = 22 / 263 = 0.08365

Z = (0.08365 - 0.12) / 0.02004

Z = −1.813872

Z = - 1.814

P(Z < −1.814) = 0.034839 (Z probability calculator)

Yes, it is unusual

0.034 < 0.05 (Hence, There is a less than 5% chance of this happening by random variation.

7 0
3 years ago
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almond37 [142]

Answer:

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Step-by-step explanation:

9=6

6*4=24 (9*4=36)

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Step-by-step explanation:

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