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nordsb [41]
3 years ago
5

Which is equivalent to (4xy-3x)^2, and what type of special product is it?

Mathematics
2 answers:
mars1129 [50]3 years ago
8 0

It's not the difference of squares, rather it is the square of a difference. That leaves a perfect square trinomial, which narrows your selection to two choices. An expression with 2 terms is not a trinomial, so that further narrows your selection. The appropriate choice is

... (4xy -3z)² = 16x²y² -24xyz +9z², a perfect square trinomial

_____

The expression you have in your problem statement has no z term, so none of the choices is applicable to that one.

maria [59]3 years ago
5 0

Answer:

The correct option is 4.

Step-by-step explanation:

The given expression is

(4xy-3z)^2

Algebraic formula:

(a-b)^2=a^2-2ab+b^2

It is a perfect square trinomial.

Using algebraic formula, we get

(4xy-3z)^2=(4xy)^2-2(4xy)(3z)+(3z)^2

(4xy-3z)^2=16x^2y^2-24xyz+9z^2

Therefore option 4 is correct.

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Slope intercept form of a line perpendicular to 3x + y = -8, and passing through (-3,1) is y=\frac{1}{3} x+2

<u>Solution:</u>

Need to write equation of line perpendicular to 3x+y = -8 and passes through the point (-3,1).

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Let required slope = x  

\begin{array}{l}{=x \times-3=-1} \\\\ {=>x=\frac{-1}{-3}=\frac{1}{3}}\end{array}

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Equation of line passing through (x_1 , y_1) and having lope of m is given by

\left(y-y_{1}\right)=\mathrm{m}\left(x-x_{1}\right)

\text { In our case } x_{1}=-3 \text { and } y_{1}=1 \text { and } \mathrm{m}=\frac{1}{3}

Substituting the values we get,

\begin{array}{l}{(\mathrm{y}-1)=\frac{1}{3}(\mathrm{x}-(-3))} \\\\ {=>\mathrm{y}-1=\frac{1}{3} \mathrm{x}+1} \\\\ {=>\mathrm{y}=\frac{1}{3} \mathrm{x}+2}\end{array}

Hence the required equation of line is found using slope intercept form

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