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Snowcat [4.5K]
3 years ago
5

a bookstore has four boxes of books each box contains 20 books on Monday the book store sold 16 books how many books remain to b

e sold​
Mathematics
1 answer:
vitfil [10]3 years ago
6 0

Answer:64

Step-by-step explanation:

You have the other 3 box's with 20 left which is 60 so all you gotta do is 20-16 which is 4

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Which of the following rational expressions has the domain restrictions X = -6 and x = 1?
Tcecarenko [31]

The domain of the function is possible values of independant varaible such that function is defined or have real values.

So the expression

\frac{(x+2)(x-3)}{(x-1)(x+6)}

is not defined for x = -6 and for x = 1, as expression becomes undefined for this values of x (Denominator becomes 0).

So answer is,

\frac{(x+2)(x-3)}{(x-1)(x+6)}

Option B is correct.

7 0
1 year ago
Which equation best represents this situation?
Harlamova29_29 [7]
Hello!

We have the difference between 30 and x(our unknown value) is equal to 17; so we just simply set it up that way. Always think of x or any variable(like in your question they use p, it can be anything u want, it’s simply a representation of an unknown value we are trying to find)as your unknown and what operation they are implying as in this case it’s subtraction as they want the difference between 30 and x.

So the answer is a. 30-p=17

Hope this helped and any questions please just ask. Thank you!
7 0
3 years ago
Starting in the 1970s, medical technology allowed babies with very low birth weight (VLBW, less than 1500 grams, about 3.3 pound
cluponka [151]

Answer:

The test statistic value using the VLBW babies as group 1 is z=-2.76±0.01 and the P-value for the test (±0.0001) is 0.0030.

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that the proportion of persons with normal birth weight that graduates from high school is significantly greater than the proportion of persons with very low birth weight that graduates from high school.

Then, the null and alternative hypothesis are:

H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2> 0

The significance level is 0.05.

The sample 1 (VLBW group), of size n1=244 has a proportion of p1=0.77049.

p_1=X_1/n_1=188/244=0.77049

The sample 2 (control group), of size n2=247 has a proportion of p2=0.79757.

p_2=X_2/n_2=197/247=0.79757

The difference between proportions is (p1-p2)=-0.02708.

p_d=p_1-p_2=0.77049-0.79757=-0.02708

The pooled proportion, needed to calculate the standard error, is:

p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{188+197}{244+247}=\dfrac{385}{491}=0.988

The estimated standard error of the difference between means is computed using the formula:

s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.988*0.012}{244}+\dfrac{0.988*0.012}{247}}\\\\\\s_{p1-p2}=\sqrt{0.00005+0.00005}=\sqrt{0.0001}=0.0098

Then, we can calculate the z-statistic as:

z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{-0.02708-0}{0.0098}=\dfrac{-0.02708}{0.0098}=-2.76

This test is a left-tailed test, so the P-value for this test is calculated as (using a z-table):

P-value=P(t

As the P-value (0.0030) is smaller than the significance level (0.05), the effect issignificant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the proportion of persons with normal birth weight that graduates from high school is significantly greater than the proportion of persons with very low birth weight that graduates from high school.

3 0
3 years ago
Hey! i’ll give brainliest please help
Phantasy [73]

Answer:

c

Step-by-step explanation:

8 0
3 years ago
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aev [14]
22%. Make it a percent and it'll be 22%.
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