Answer:
The area of the triangle is 18 square units.
Step-by-step explanation:
First, we determine the lengths of segments AB, BC and AC by Pythagorean Theorem:
AB
![AB = \sqrt{(5-2)^{2}+[6-(-1)]^{2}}](https://tex.z-dn.net/?f=AB%20%3D%20%5Csqrt%7B%285-2%29%5E%7B2%7D%2B%5B6-%28-1%29%5D%5E%7B2%7D%7D)
BC
AC
![AC = \sqrt{(-1-2)^{2}+[4-(-1)]^{2}}](https://tex.z-dn.net/?f=AC%20%3D%20%5Csqrt%7B%28-1-2%29%5E%7B2%7D%2B%5B4-%28-1%29%5D%5E%7B2%7D%7D)
Now we determine the area of the triangle by Heron's formula:
(1)
(2)
Where:
- Area of the triangle.
- Semiparameter.
If we know that , and , then the area of the triangle is:
The area of the triangle is 18 square units.
Answer:
E. is the correct answer
Step-by-step explanation:
Answer:
4500
Step-by-step explanation:
It is a.
You multiply 9.3 and 2.5 together and get 23.25
Then just add the exponents 6+3 is 9
So the answer is 23.25 x 10^9
Hope this helps!!
Answer:
$1.28
Note for you:
I hope this helps!
Answer and Step-by-step explanation:
The computation is shown below;
As we know that
The simple interest is
Simple interest = Principal × rate × time
For Account A, the principal would be
2 = Principal × 3.2% × 3
So, the principal is $20.83
For account B, the principal would be
38.50 = Principal × 2.2% × 30
So, the principal is $58.33
Now the interest for both the accounts are as follows
For account 1
= $20.83 × 3.2%
= $0.67
And, for the account 2
= $58.33 × 2.2%
= $1.28
As it can be seen that the account 2 has the highest interest
The same is to be considered
