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Paladinen [302]
4 years ago
5

Given the domain {-4, 0, 5}, what is the range for the relation 12x + 6y = 24?A.{12, 4, -6}B.{-4, 4, 14}C.{2, 4, 9}D.{-12, -4, 6

}
Mathematics
2 answers:
Ymorist [56]4 years ago
6 0

Answer:{12, 4, -6}

Step-by-step explanation:

Leokris [45]4 years ago
4 0

Answer:

{12, 4, -6}

Step-by-step explanation:

The relation is given by the equation as 12x + 6y = 24 ........... (1)

Now, the domain of this function is {-4, 0, 5}

We have to find the range of this function corresponding to the given domain.

Now, for x = - 4,  

12(-4) + 6y = 24 {From equation (1)}

⇒ 6y = 72

⇒ y = 12

Now, for x = 0,  

12(0) + 6y = 24 {From equation (1)}

⇒ 6y = 24

⇒ y = 4  

Now, for x = 5,  

12(5) + 6y = 24 {From equation (1)}

⇒ 6y = -36

⇒ y = -6

Hence, the range for the relation is {12, 4, -6} (Answer)

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a gear ratio is the ratio of the teeth on the front sprocket and the teeth on the rear sprocket.if a bike has 36 teeth on the fr
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Answer:

3 : 1

Step-by-step explanation:

ratio = teeth on front sprocket : teeth on rear sprocket

       = 36 : 12 ( divide both parts of the ratio by 12 )

       = 3 : 1 ← in simplest form


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3 years ago
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Find the value of p if Cos 49 = Sin(p+10)
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Answer:Do you mean find p?  If so then p+10 = 90 - 49, so p = 31°.  Another possibility is in the second quadrant where p + 10 = 180 - 41 so p = 129°  (The 41 comes from the first p+10, i.e. 31+10 = 41),

Check:

Step-by-step explanation:

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3 years ago
What is the median number for the numbers 4, 8, 10, 5, 9
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8 0
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What is the midpoint of the segment?
Andre45 [30]
The midpoint of a segment A(x_A;\ y_A);\ B(x_B;\ y_B)\\\\M_{AB}\left(\dfrac{x_A+x_B}{2};\ \dfrac{y_A+y_B}{2}\right)

A(-12;-3); B(3;-8)

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7 0
3 years ago
The computers of six faculty members in a certain department are to be replaced. Two of the faculty members have selected laptop
Anettt [7]

Answer:

a. \frac{1}{15}

b. \frac{2}{5}

c. \frac{14}{15}

d. \frac{8}{15}

Step-by-step explanation:

Given that there are two laptop machines and four desktop machines.

On a day, 2 computers to be set up.

To find:

a. probability that both selected setups are for laptop computers?

b. probability that both selected setups are desktop machines?

c. probability that at least one selected setup is for a desktop computer?

d. probability that at least one computer of each type is chosen for setup?

Solution:

Formula for probability of an event E can be observed as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

a. Favorable cases for Both the laptops to be selected = _2C_2 = 1

Total number of cases = 15

Required probability is \frac{1}{15}.

b. Favorable cases for both the desktop machines selected = _4C_2=6

Total number of cases = 15

Required probability is \frac{6}{15} = \frac{2}{5}.

c. At least one desktop:

Two cases:

1. 1 desktop and 1 laptop:

Favorable cases = _2C_1\times _4C_1 = 8

2. Both desktop:

Favorable cases = _4C_2=6

Total number of favorable cases = 8 + 6 = 14

Required probability is \frac{14}{15}.

d. 1 desktop and 1 laptop:

Favorable cases = _2C_1\times _4C_1 = 8

Total number of cases = 15

Required probability is \frac{8}{15}.

8 0
4 years ago
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