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Vlad [161]
2 years ago
13

For each equation find all the roots PLEASE HELP I AM SO CONFUSED

Mathematics
1 answer:
worty [1.4K]2 years ago
3 0

Answer:

Step-by-step explanation:

13.

x³-x²-x-2=0

x³-2x²+x^2-2x+x-2=0

x²(x-2)+x(x-2)+1(x-2)=0

(x-2)(x²+x+1)=0

x-2=0,x=2

x²+x+1=0

x=\frac{-1\pm\sqrt{1^2-4*1*1}}{2*1}} \\x=\frac{-1 \pm\sqrt{1-4} }{2} \\x=\frac{-1 \pm\sqrt{-3}}{2} \\x=\frac{-1\pm\sqrt{3} \iota}{2}

<em>12.</em>

<em>3x^4-11x³+15x²-9x+2=0</em>

<em>\[3x^4-3x^3-8x^3+8x²+7x²-7x-2x+2=0\]</em>

<em>3x³(x-1)-8x²(x-1)+7x(x-1)-2(x-1)=0</em>

<em>(x-1)[3x³-8x²+7x-2]=0</em>

<em>x-1=0,gives x=1</em>

<em>3x³-8x²+7x-2=0</em>

<em>3x³-3x²-5x²+5x+2x-2=0</em>

<em>3x²(x-1)-5x(x-1)+2(x-1)=0</em>

<em>(x-1)(3x²-5x+2)=0</em>

<em>x-1=0,gives x=1</em>

<em>3x²-5x+2=0</em>

<em>3x²-3x-2x+2=0</em>

<em>3x(x-1)-2(x-1)=0</em>

<em>(x-1)(3x-2)=0</em>

<em>x-1=0,gives x=1</em>

<em>3x-2=0, gives x=2/3</em>

<em>so roots are 2/3,1,1,1</em>

<em />

<em />

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<u>According to question</u>

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