Question

the singh and robinson families planned a trip to busch gardens. they needed to buy one ticket per person and then pay for parking. the singh's spent $335 for 5 people and the robinsons spent $ 465 for 7 people. how much did each ticket cost? How much was parking

Answer 1

Let x represent cost of each ticket and y represent cost of parking.

We have been given that the Singh's spent $335 for 5 people and parking. We can represent this information in an equation as:

$5x+y=335...(1)$

We are also told that the Robinson spent $465 for 7 people and parking. We can represent this information in an equation as:

$7x+y=465...(2)$

Now we will use elimination method to solve our given system of equations.

Upon subtracting equation (1) from equation (2), we will get:

$7x-5x+y-y=465-335$

$2x=130$

$\frac{2x}{2}=\frac{130}{2}$

$x=65$

Therefore, the each ticket costs $65.

Upon substituting $x=65$ in equation (1), we will get:

$5(65)+y=335$

$325+y=335$

$325-325+y=335-325$

$y=10$

Therefore, the parking costs $10.