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mash [69]
3 years ago
8

the singh and robinson families planned a trip to busch gardens. they needed to buy one ticket per person and then pay for parki

ng. the singh's spent $335 for 5 people and the robinsons spent $ 465 for 7 people. how much did each ticket cost? How much was parking
Mathematics
1 answer:
hjlf3 years ago
5 0

Let x represent cost of each ticket and y represent cost of parking.

We have been given that the Singh's spent $335 for 5 people and parking. We can represent this information in an equation as:

5x+y=335...(1)

We are also told that the Robinson spent $465 for 7 people and parking. We can represent this information in an equation as:

7x+y=465...(2)

Now we will use elimination method to solve our given system of equations.

Upon subtracting equation (1) from equation (2), we will get:

7x-5x+y-y=465-335

2x=130

\frac{2x}{2}=\frac{130}{2}

x=65

Therefore, the each ticket costs $65.

Upon substituting x=65 in equation (1), we will get:

5(65)+y=335

325+y=335

325-325+y=335-325

y=10

Therefore, the parking costs $10.

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