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MrRa [10]
3 years ago
11

What does a program do when it needs to read a file?

Computers and Technology
1 answer:
Alja [10]3 years ago
5 0
Hello <span>Quinshayewilli7701 </span>

Question: What does a program do when it needs to read a file?<span>
Answer: It goes the address area, which is the front of the hard drive with the links to the areas on the hard drive where the file is located.

Hope This helps
-Chris</span>
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Which of the following functions needed to implement the information security program evaluates patches used to close software v
solong [7]

Answer:

a. Systems testing

Explanation:

According to my research on information technology, I can say that based on the information provided within the question the term being defined is called System Testing. Like mentioned in the question, this is a technique used in order to evaluate the complete system the system's compliance against specified requirements, which tests its functionalities from an end-to-end perspective in order to evaluates patches used to close software vulnerabilities and make sure it complies with all policies.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

6 0
3 years ago
16. (PPT) You can use features on the Video Tools Playback tab to adjust how and when the video plays during the slide
Nezavi [6.7K]

Answer:

a. True

Explanation:

5 0
2 years ago
QUICK HELP ME PLEASE
Sholpan [36]

Answer: Cable Internet access requires the setting up of fiber cables. It is the fastest type of Internet access technology. that's the answer

4 0
3 years ago
rocess inputs using the following 1) Write a function that inputs numerical digits in the range of an unsigned short. 2) Write a
yawa3891 [41]

Answer:

 /* sizeof.c—Program to tell the size of the C variable */

 /*      type in bytes */

 

 #include <stdio.h>

 

   int main(void)

  {

  printf( "\nA char   is %d bytes", sizeof( char ));

  printf( "\nAn int   is %d bytes", sizeof( int ));

  printf( "\nA short   is %d bytes", sizeof( short ));

  printf( "\nA long   is %d bytes", sizeof( long ));

  printf( "\nA long long is %d bytes\n", sizeof( long long));

  printf( "\nAn unsigned char is %d bytes", sizeof( unsigned char ));

  printf( "\nAn unsigned int  is %d bytes", sizeof( unsigned int ));

  printf( "\nAn unsigned short is %d bytes", sizeof( unsigned short ));

  printf( "\nAn unsigned long is %d bytes", sizeof( unsigned long ));

  printf( "\nAn unsigned long long is %d bytes\n",

   sizeof( unsigned long long));

 printf( "\nA float   is %d bytes", sizeof( float ));

 printf( "\nA double  is %d bytes\n", sizeof( double ));

 printf( "\nA long double is %d bytes\n", sizeof( long double ));

return 0;

 }

2. #include<stdio.h>

int main(){

  int num,reverse_number;

  //User would input the number

  printf("\nEnter any number:");

  scanf("%d",&num);

  //Calling user defined function to perform reverse

  reverse_number=reverse_function(num);

  printf("\nAfter reverse the no is :%d",reverse_number);

  return 0;

}

int sum=0,rem;

reverse_function(int num){

  if(num){

     rem=num%10;

     sum=sum*10+rem;

     reverse_function(num/10);

  }

  else

     return sum;

  return sum;

}

3.  

#include <bits/stdc++.h>  

 

using namespace std;  

/* Iterative function to reverse digits of num*/

int reversDigits(int num)  

{  

   int rev_num = 0;  

   while(num > 0)  

   {  

       rev_num = rev_num*10 + num%10;  

       num = num/10;  

   }  

   return rev_num;  

}  

 

/*Driver program to test reversDigits*/

int main()  

{  

   int num = 4562;  

   cout << "Reverse of no. is "

        << reversDigits(num);  

   getchar();  

   return 0;

4 0
3 years ago
What will the following code display? int numbers[4] = { 99, 87 }; cout &lt;&lt; numbers[3] &lt;&lt; endl; a. 87 b.0 d. 34. What
pishuonlain [190]

Answer:

1. The output is 0

2. Each element in the array is initialized to 0.0

Explanation:

Solving (a): The output of the code

We have:

<em>int numbers[4] = { 99, 87 }; </em>

<em>cout << numbers[3] << endl;</em>

<em />

The first line initializes the 0 and 1 index of the array to 99 and 87, respectively.

Other elements will be 0, by default.

So, the following code segment will output 0

<em>cout << numbers[3] << endl; </em>

<em />

Solving (b): What the given code will do?

The first and second line declares an array of 5 elements

However, the following iteration will only initialize the array with 0.0 starting from the second

<em>for(int i = 2; i <= SIZE; i++) { x[i] = 0.0; }</em>

<em />

Because, the counter is initialized to start from the second index.

7 0
3 years ago
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