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nikdorinn [45]
4 years ago
11

PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
mestny [16]4 years ago
6 0
D is the correct answer between those two
vladimir2022 [97]4 years ago
4 0
D-----------------------
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Speedy offers a better price for one day renta
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4 years ago
A teacher gives a test to a large group of students. The results are closely approximated by a normal curve. Teh mean is 73, wit
zavuch27 [327]

Answer:

The bottom for an A is 75. Round to the nearest whole number as needed.

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Let X the random variable that represent the scores on this case, and for this case we know the distribution for X is given by:

X \sim N(\mu=73,\sigma=7)  

And let \bar X represent the sample mean, the distribution for the sample mean is given by:

\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})

2) The bottom for an A is _____. Round to the nearest whole number as needed.

And we want the top 5.5% of the scores, so we need a value a such that:

P(X>a)=0.055 or P(X

We need on the right tail of the distribution a value a that gives to us 94.5% of the area below and 5.5% of the area above. Both conditions are equivalent.

Let's use the condition P(X, the best way to solve this problem is using the z score with the following formula:

z=\frac{x-\mu}{\sigma}

So we need a value from the normal standard distribution that accumulates 0.945 of the area on the left and 0.055 on the right. This value on this case is 1.598 and we can founded with the following code in excel:

"=NORM.INV(0.945,0,1)"

If we apply the z score formula to our case we have this:

P(X

So then based on the equalities we have this:

\frac{a-73}{7}=1.598

And if we solve for a we got:

a=(7*1.598) +73=84.186

So then we need a score of 84.186 rounded to the nearest whole number 75 or higher in order to get an A

8 0
3 years ago
How can i do this equation 8y-(5y+2)=16
AlladinOne [14]

Answer:

y=6

Step-by-step explanation:

8y-5y-2=16

8y-5y=16+2

3y=18

y=18/3

y=6

4 0
4 years ago
Read 2 more answers
A red car and a blue car are traveling at the same speed. The red car drives 3 hours. The blue car drives another half hour and
Ganezh [65]

. Distance = Speed * Time  

Let s represent the speed of the cars in miles per hour. The problem statement tells you  

.. red car distance + 25 miles = blue car distance  

.. s*3 + 25 = s*(3 + 0.5)  

.. 25 = 0.5s ... subtract 3s from both sides  

.. 50 = s ... multiply by 2  

The speed of the red and blue cars is 50 miles per hour.  



7 0
4 years ago
Read 2 more answers
Can you help me please i do. not get this
xenn [34]

Answer:

5 13/24

Step-by-step explanation:

(10 5/12) - (4 7/8) = (10 +5/12) -(4 +7/8)

... = (10 -4) +(5/12 -7/8)

... = 6 + (5/12 -7/8) . . . . . read on for how to simplify this

_____

<em>Adding fractions</em>

Adding fractions can be done in a mechanical sort of way using the formula ...

... a/b + c/d = (ad +bc)/(bd)

Here, we have a=5, b=12, c=-7, d=8, so the sum is ...

... (5·8 +12(-7))/(12·8) = (40 -84)/96 = -44/96

The numerator and denoinator of this fraction are both multiples of 4, so we can reduce the fraction.

... -44/96 = 4(-11)/(4·24) = -11/24

_____

<em>Back to the problem at hand</em>

... 6 + (5/12 -7/8) = 6 - 11/24

Now, we know that 1 = 24/24, so when we subtract 11/24 from 1, we get ...

... 1 - 11/24 = 24/24 - 11/24 = (24 -11)/24 = 13/24

So, our expression 6 - 11/24 can be rewritten as ...

... 6 -11/24 = (5 + 1) - 11/24 = 5 + (1 -11/24) = 5 13/24

Summary

... (10 5/12) - (4 7/8) = 5 13/24

_____

<em>Another way to add fractions</em>

The way to add fractions that is commonly taught is to first find a common denominator. Here that means you want to find the smallest number that is a multiple of both 12 and 8, the two denominators. You may recognize that number as being 24 = 12·2 = 3·8. (The methods of finding the common denominator (least common multiple) for numbers not in your memorized multiplication tables are not easy to describe.)

The next step in this method is to rewrite the fractions so they each have this denominator. The multipliers in the above equation are helpful for that purpose.

... 5/12 = (5·2)/(12·2) = 10/24

... 7/8 = (7·3)/(8·3) = 21/24

Now, the subtraction can proceed easilly:

... 10/24 - 21/24 = (10 -21)/24 = -11/24 . . . . . same result as above

8 0
4 years ago
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