So 1st consider that it's a square! That's very important. So for a square, all 4 sides are equal.
And now considering that the given information is the diameter. So any angle made at the circle extended from the 2 points of diameter gives an angle of 90°
Now consider one triangle. So we already know that 2 sides of the triangle are equal (because they are 2 sides of a square) , has a side of 10 (diameter) and and angle of 90°. So remaining 2 angles are 45°
Now solve it by applying
<h3>
Answer: $628 </h3>
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Work Shown:
x = Ali's share
4x = Pip's share, because it is four times bigger due to the ratio 4:1
x+4x = 5x = total amount of money = 785
5x = 785
x = 785/5
x = 157 dollars is Ali's share
4x = 4*157 = 628 dollars is Pip's share
Note that 157+628 = 785 to help confirm the answer.
The <u>correct answer</u> is:
B) The variables are height and time. For the first part of the graph, the height is increasing slowly, which means the hiker is walking up a gentle slope. Flat parts of the graph show where the elevation does not change, which means the trail is flat here. The steep part at the end of the graph shows that the hiker is descending a steep incline.
Explanation:
The variables are marked on the graph. Time is marked along the x-axis, which means it is the independent variable. Height is marked along the y-axis, which means it is the dependent variable.
The first part of the graph rises slowly. This means the elevation does not change much over the time; this would be consistent with a gentle slope being climbed.
The flat areas are where the elevation does not change. This would be consistent with the hiker resting.
The steep decrease at the end shows that the elevation goes down quickly. This is consistent with the hiker climbing down a steep slope.
Answer:
you do a line that goes through b but doesn't go through the circle
F(x + 1) = (5/2)*f(x)
f(x + 1) = 2.5*f(x), f(1) = 3.2
f(2) = 2.5f(1) = 2.5*3.2 = 8
<span>f(3) = 2.5f(2) = 2.5*8 = 20
</span>
f(4) = 2.5f(3) = 2.5*20 = 50
<span>f(5) = 2.5f(4) = 2.5*50 = 125</span>
