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8_murik_8 [283]
3 years ago
12

Please help ASAP ...AP is arithmetic progression

Mathematics
2 answers:
solmaris [256]3 years ago
8 0

Answer:

8-(5-x)=2x-8  ⇒ common difference

Step-by-step explanation:

5-x,8,2x

to find the arithmetic difference of the progression

8-(5-x)=2x-8  ⇒ common difference

and solve for x

8-5+x=2x-8

3+x=2x-8

x=11

koban [17]3 years ago
4 0

Answer:

The common difference is  d = 14

Step-by-step explanation:

An arithmetic progression should verify that the difference between any two consecutive elements of the progression is always the same number.

Therefore, making first the difference between second and first terms, we have:

8 - (5 - x) = 8 - 5 + x = 3 + x  (which should be the actual common difference)

Now the difference between the third and second terms:

2 x - 8 = 2 x - 8

and should be also equal to the common difference we found in our first step:

2 x - 8 = 3 + x

solving for x:

2 x - x = 8 + 3

x = 11

which makes the common difference : 3 + 11 = 14

and the actual sequence: -6, 8, 22

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abruzzese [7]
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4 0
3 years ago
Find each product<br> y(9 + 2y)
yanalaym [24]
Y (9 + 2y)

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3 0
3 years ago
Read 2 more answers
Please show work. thank you!​
ioda

Answer:

\large\boxed{h=\dfrac{\sqrt{703}}{2}ft\approx13.26ft}

Step-by-step explanation:

Look at the picture.

Use the Pythagorean theorem:

leg^2+leg^2=hypotenuse^2

We have:

leg=\dfrac{9}{2}ft\\\\hypotenuse=14ft\\\\leg=h

Substitute:

\left(\dfrac{9}{2}\right)^2+h^2=14^2

\dfrac{81}{4}+h^2=196                <em>multiply both sides by 4</em>

81+4h^2=784             <em>subtract 81 from both sides</em>

4h^2=703            <em>divide both sides by 4</em>

h^2=\dfrac{703}{4}\to h=\sqrt{\dfrac{703}{4}}\\\\h=\dfrac{\sqrt{703}}{\sqrt4}\\\\h=\dfrac{\sqrt{703}}{2}\\\\h\approx13.26

5 0
4 years ago
Picture explains everything. ty
Dmitry_Shevchenko [17]

Answer:

B

Step-by-step explanation:

i hope this helps a bit.

3 0
3 years ago
Help me please I’m not sure about this
frutty [35]

easy, 36/6=6

6 people, right?

7 0
3 years ago
Read 2 more answers
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