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emmasim [6.3K]
3 years ago
6

The double number line shows that 5 pounds of avocados cost $9.

Mathematics
1 answer:
natali 33 [55]3 years ago
8 0
$9 divided by 5 = 1.8

A pound of avocados is $1.80
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Tim Worker is doing his budget. He discovers that the average electric bill for the year was $206.00 with a standard deviation o
ivanzaharov [21]

Answer:

  • -2.2
  • 1.4%
  • -0.6
  • 27.4%
  • 26%
<h3>Step-by-step explanation:</h3>

The z-value is computed from ...

... z = (x -µ)/σ

... z = (184 -206)/10 = -2.2 . . . . for $184

... z = (200 -206)/10 = -0.6 . . . . for $200

You can look up these values in a normal distribution table, or you can use an appropriate calculator to find the corresponding percentiles.

... -2.2 corresponds to the 1.390 percentile. (That amount of area is below -2.2 standard deviations from the mean.)

... -0.6 corresponds to the 27.425 percentile.

Subtracting the two percentages gives the percentage of expenses between $184 and $200. That number is 26.035% ≈ 26%.

_____

<em>Comment on the calculator display</em>

The difference that got cut off from the display in the attachment is ...

... 0.2603496703

The <em>normalcdf( )</em> function requires a lower limit. Using -8 standard deviations is effectively equivalent to -∞ for this purpose, as any lower number has no effect on the least-significant digits of the result.

7 0
3 years ago
Find the coefficient of variation for each of the two sets of data, then compare the variation. Round results to one decimal pla
svp [43]

Here is  the correct computation of the question given.

Find the coefficient of variation for each of the two sets of data, then compare the variation. Round results to one decimal place. Listed below are the systolic blood pressures (in mm Hg) for a sample of men aged 20-29 and for a sample of men aged 60-69.

Men aged 20-29:      117      122     129      118     131      123

Men aged 60-69:      130     153      141      125    164     139

Group of answer choices

a)

Men aged 20-29: 4.8%

Men aged 60-69: 10.6%

There is substantially more variation in blood pressures of the men aged 60-69.

b)

Men aged 20-29: 4.4%

Men aged 60-69: 8.3%

There is substantially more variation in blood pressures of the men aged 60-69.

c)

Men aged 20-29: 4.6%

Men aged 60-69: 10.2 %

There is substantially more variation in blood pressures of the men aged 60-69.

d)

Men aged 20-29: 7.6%

Men aged 60-69: 4.7%

There is more variation in blood pressures of the men aged 20-29.

Answer:

(c)

Men aged 20-29: 4.6%

Men aged 60-69: 10.2 %

There is substantially more variation in blood pressures of the men aged 60-69.

Step-by-step explanation:

From the given question:

The coefficient of variation can be determined by the relation:

coefficient \ of  \ variation = \dfrac{standard \ deviation}{mean}*100

We will need to determine the coefficient of variation both men age 20 - 29 and men age 60 -69

To start with;

The coefficient of men age 20 -29

Let's first find the mean and standard deviation before we can do that ;

SO .

Mean = \dfrac{\sum \limits^{n}_{i-1}x_i}{n}

Mean = \frac{117+122+129+118+131+123}{6}

Mean = \dfrac{740}{6}

Mean = 123.33

Standard deviation  = \sqrt{\dfrac{\sum (x_i- \bar x)^2}{(n-1)} }

Standard deviation =\sqrt{\dfrac{(117-123.33)^2+(122-123.33)^2+...+(123-123.33)^2}{(6-1)} }

Standard deviation  = \sqrt{\dfrac{161.3334}{5}}

Standard deviation = \sqrt{32.2667}

Standard deviation = 5.68

The coefficient \ of  \ variation = \dfrac{standard \ deviation}{mean}*100

coefficient \ of  \ variation = \dfrac{5.68}{123.33}*100

Coefficient of variation = 4.6% for men age 20 -29

For men age 60-69 now;

Mean = \dfrac{\sum \limits^{n}_{i-1}x_i}{n}

Mean = \frac{   130 +    153    +  141  +    125 +   164  +   139}{6}

Mean = \dfrac{852}{6}

Mean = 142

Standard deviation  = \sqrt{\dfrac{\sum (x_i- \bar x)^2}{(n-1)} }

Standard deviation =\sqrt{\dfrac{(130-142)^2+(153-142)^2+...+(139-142)^2}{(6-1)} }

Standard deviation  = \sqrt{\dfrac{1048}{5}}

Standard deviation = \sqrt{209.6}

Standard deviation = 14.48

The coefficient \ of  \ variation = \dfrac{standard \ deviation}{mean}*100

coefficient \ of  \ variation = \dfrac{14.48}{142}*100

Coefficient of variation = 10.2% for men age 60 - 69

Thus; Option C is correct.

Men aged 20-29: 4.6%

Men aged 60-69: 10.2 %

There is substantially more variation in blood pressures of the men aged 60-69.

4 0
3 years ago
Renee has a triangular garden with an area of 24 square feet. Which drawing shows Renee's garden?
gulaghasi [49]

Answer:

The picture that represent her drawing is uploaded below. The height is 8 ft and the base is 6 ft.

Step-by-step explanation:

Renee garden is triangular in shape . The area of the triangular garden is given as 24 ft² . The area of a triangle can be represented below.

Area of a triangle = 1/2bh

where

b = base

h = height

The drawing that represent Renee drawing is given below. The height is 8 ft and the base is 6 ft .

Using the formula

Area of a triangle = 1/2bh

Area of a triangle = 1/2 × 6 × 8

Area of a triangle = 48/2

Area of a triangle = 24 ft²

6 0
3 years ago
Read 2 more answers
In the solution of the equation 5 + 3x = -2x + 9, 2x is added to the equation first. Which of the following should be done next?
Ivanshal [37]
3x + 2x = 9 - 5
5x = 4 
x = 0.8
7 0
4 years ago
What is the value of x in the equation
bogdanovich [222]

Answer:

D 57

Step-by-step explanation:

The value of X

3 0
4 years ago
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