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Verizon [17]
4 years ago
5

The answer to f(x) = x2 + 3

Mathematics
1 answer:
Dominik [7]4 years ago
8 0
Is the x2 squared or is it just 2x.
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The edge of a cube was found to be 30 cm with a possible error in measurement of 0.2 cm. Use differentials to estimate the maxim
rjkz [21]

Answer:

Maximum volume error = ±540 cm³

Relative error = 0.02

Percentage error = 2%

Step-by-step explanation:

Relative error : The ratio of volume error to the total volume.

Percentage error: The product of relative error and 100.

The volume of a cube is = side^3

v =x³

Differentiate with respect to x

\frac{dv}{dx} = 3x^2

\Rightarrow dv = 3x^2 dx

Here are x = 30 cm and dx= ±0.2 cm

∴ dv = 3×(30 cm)² (±0.2 cm)

      =±540 cm³

The volume of the cube = 30³ cm ³ = 27,000 cm³

Then the relative error

=\frac{dv}{v}

=\frac{540 cm^3}{27,000 cm^3}

= 0.02.

The percentage error

= (0.02×100)

=2%

7 0
3 years ago
Help me plz
irakobra [83]

Answer:

I could do 1 and 3

1) 2x-3y=-2 ....1

-

2x+y=14......2

=-4y=-16

y=4

<u>Substitute</u><u> </u><u>(</u><u>y</u><u>=</u><u>4</u><u>)</u><u> </u><u>into</u><u> </u><u>equation</u><u> </u><u>1</u>

2x-3 (4)=-2

2x-12=-2

2x=-2+12

2x=10

×=5

3) 5x+5y=20....1

-

-3x+5y=4......2

=8x=16

x=2

<u>S</u><u>ubstitute</u><u> </u><u>(</u><u>x</u><u>=</u><u>2</u><u>)</u><u> </u><u>into</u><u> </u><u>equation</u><u> </u><u>1</u>

<u>5</u><u> </u><u>(</u><u>2</u><u>)</u><u>+</u><u>5y</u><u>=</u><u>20</u>

<u>10</u><u>+</u><u>5y</u><u>=</u><u>20</u>

<u>5y</u><u>=</u><u>20-10</u>

<u>5y</u><u>=</u><u>10</u>

<u>y</u><u>=</u><u>2</u>

5 0
3 years ago
Read 2 more answers
X2+nx -mx-nm = 0<br> Plzzzzzzzzzzzzzzzz help me
loris [4]

Answer:

I don’t know

Step-by-step explanation:

6 0
3 years ago
Which arrow indicates the probability of choosing a blue marble from a bag of five red marbles and fifteen blue marbles?
tangare [24]

Answer: Its c

Step-by-step explanation: hope it helps :)

8 0
2 years ago
Are these two lines parallel, perpendicular or neither
Deffense [45]
They are Perpendicular
6 0
3 years ago
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