3 years ago

5. Which equation is of a circle that has a center at

Mathematics

1 answer:

Basile [38]3 years ago

5 0

Answer:

$\large\boxed{D.\ (x-3)^2+(y+2)^2=81}$

Step-by-step explanation:

The standard form of an equation of a circle:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have the center at (3, -2) and the radius r = 9. Substitute:

$(x-3)^2+(y-(-2))^2=9^2\\\\(x-3)^2+(y+2)^2=81$

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