Question

(5x^2+20x) ÷(x+4) divide, it's really important, I thank you for the people who help me in this :)

Answer 1

Answer:

5x

Step-by-step explanation:

Given expression: $\frac{5x^2+20x}{x+4}$

Take the common number 5 outside in the numerator.

$\frac{5x^2+20x}{x+4}=\frac{5(x^2+4x)}{x+4}$

Now, take x common in both the terms in numerator.

$\frac{5(x^2+4x)}{x+4}=\frac{5x(x+4)}{x+4}$

Cancel out the common factor in the both numerator and denominator.

$\frac{5x(x+4)}{x+4}=5x$

Hence, the answer is 5x.