Answer:
107/21
Step-by-step explanation:
re - phrase the question algebraically:
-14/3 + y = 3/7
LCM of 3 and 7 = 21
-98/21 + y = 9/21
what should be added to -98 to make 9?
answer: 107
therefore answer: 107/21
Hope this helps.
Good Luck
Wat r u asking about this problem
(a) From the histogram, you can see that there are 2 students with scores between 50 and 60; 3 between 60 and 70; 7 between 70 and 80; 9 between 80 and 90; and 1 between 90 and 100. So there are a total of 2 + 3 + 7 + 9 + 1 = 22 students.
(b) This is entirely up to whoever constructed the histogram to begin with... It's ambiguous as to which of the groups contains students with a score of exactly 60 - are they placed in the 50-60 group, or in the 60-70 group?
On the other hand, if a student gets a score of 100, then they would certainly be put in the 90-100 group. So for the sake of consistency, you should probably assume that the groups are assigned as follows:
50 ≤ score ≤ 60 ==> 50-60
60 < score ≤ 70 ==> 60-70
70 < score ≤ 80 ==> 70-80
80 < score ≤ 90 ==> 80-90
90 < score ≤ 100 ==> 90-100
Then a student who scored a 60 should be added to the 50-60 category.
The answer is
When x = 4
Y = 4
Maybe the answer is correct
Answer:
The answer to your question is : f(-2) = 2
Step-by-step explanation:
Just look for -2 in the x- axis and look for some line or point, vertical to number two.
In your example you can find a point two units upward the x-axis.
