Answer:
The sampling distribution of X, for a sample of size 16, will be approximately normal with mean 2 mm and standard deviation 0.01 mm.
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean 
and standard deviation 
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean and standard deviation 
.
For the population:
Mean 2 mm, standard deviation 0.04 mm
Describe the sampling distribution of X (for a sample of size 16).
Sample of size 16 means that 
By the Central Limit Theorem, approximately normal with mean 2 and standard deviation 
<em>Greetings!</em>
In order to round to the nearest million, we will have to move the decimal 5 places to the left.
0.0000512 will be your answer.
<em>Hope this helps!</em>
~Fluerie
The answer is C)22.
If each package has 4, you divide 86 by 4 and get 21.5. You round up since you’ll need 2 out of the 4 bulbs in the last package.
Answer:
Step-by-step explanation:
a. 0.315 = 3.15 x 10^-1
b. 5,820,000,000 = 5.82 x 10^9
Answer:
-17x - 21
Step-by-step explanation:
-4 + 5x - 17 - 22x
(-4 - 17) + (5x - 22x)
(-21) + (-17x)
-17x - 21
