Question

An activity has an optimistic time estimate of 25 days, a most likely estimate of 29 days, and a pessimistic estimate of 34 days. What is the expected duration of the activity

Answer 1

The expected duration of the activity is 29 days and 4 hours.

Step-by-step explanation:

Step 1:

The optimistic time, $t_{o}$ = 25 days,

The most likely estimate, $t_{m}$ = 29 days.

The pessimistic time, $t_{p}$ = 34 days.

According to PERT, the expected duration of the activity, $t_{e} = \frac{t_{0}+4t_{m} +t_{p} }{6}.$

Step 2:

By substituting the given values, we get$t_{e} = \frac{t_{0}+4t_{m} +t_{p} }{6} = t_{e} = \frac{25+4(29) +34 }{6} = \frac{175}{6} = 29.1666.$

0.1666 days = $0.1666 (24) = 3.9999 hours.$

29.1666 days approximately equal 29 days and 4 hours.