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Ymorist [56]
3 years ago
13

How many solutions does the equation have? 7x +3 - x=3(1 + 2x) (A) 0 (B) 1. (C) infinitely many​

Mathematics
1 answer:
tekilochka [14]3 years ago
5 0

Answer:

C) Infinitely many

Step-by-step explanation:

7x+3-x=3(1+2x)

6x+3=3+6x

Subtract 3 from both sides

6x = 6x

Infinitely many solutions

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Help me if tou don't then no brainlist for you​
Murljashka [212]

Answer:

Equal to 1,204-299

Step-by-step explanation:

Anything divided by 1 is equal to itself.

8 0
4 years ago
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What fraction is bigger 2/9 or 3/4
IceJOKER [234]

Answer:

Step-by-step explanation:

Find the least common denominator or LCM of the two denominators:

LCM of 3 and 9 is 9

For the 1st fraction, since 3 × 3 = 9,

2

3

=

2 × 3

3 × 3

=

6

9

Likewise, for the 2nd fraction, since 9 × 1 = 9,

4

9

=

4 × 1

9 × 1

=

4

9

Since the denominators are now the same, the fraction with the bigger numerator is the greater fraction

6

9

>

4

9

or

2

3

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4

9

5 0
3 years ago
Read 2 more answers
Determine the possible rational zeros of this polynomial function using the rational zeros theorem:
sleet_krkn [62]

Answer:

See answer below

Step-by-step explanation:

The possible zeroes are p/q where p is factors of the constant and q is factors of the coefficient of the largest degree.

This means possible zeroes are ±15/4, ±5/4, ±3/4, ±1/4, ±15/2, ±5/2, ±3/2, ±1/2, ±15, ±5, ±3, ±1.

3 0
3 years ago
You invested $900 and received $1,548.00 after nine years. What was the interest rate?
xenn [34]
.08 or 8%

Explanation 900x 0.08 is 72
72x9 is 648
900+648 = 1548
8 0
2 years ago
determine the value of m and n for mx^3 +20x^2+ nx-36 when divided by (x+1) gives remainder 0 and when divided by (x-2) gives re
soldi70 [24.7K]

Given:

The given polynomial is

mx^3+20x^2+nx-36

When it divided by (x+1) gives remainder 0 and when divided by (x-2) gives remainder of 45.

To find:

The values of m and n.

Solution:

According to the remainder theorem, if a polynomial P(x) is divided by (x-c), then the remainder is P(c).

Let the given polynomial be P(x).

P(x)=mx^3+20x^2+nx-36

When it divided by (x+1) gives remainder 0. So, P(-1)=0.

P(-1)=m(-1)^3+20(-1)^2+n(-1)-36

0=-m+20-n-36

0=-m-n-16

m+n=-16                   ...(i)

When P(x) is divided by (x-2) gives remainder of 45. So, P(2)=0

m(2)^3+20(2)^2+n(2)-36=45

8m+80+2n-36=45

8m+2n+44=45

8m+2n=45-44

8m+2n=1                  ...(ii)

Multiply 2 on both sides of (i).

2m+2n=-32                   ...(iii)

Subtract (iii) from (ii).

6m=33

m=\dfrac{33}{6}

m=5.5

Putting m=5.5 in (i), we get

5.5+n=-16

n=-16-5.5

n=-21.5

Therefore, the values of m and n are 5.5 and -21.5 respectively.

7 0
3 years ago
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