lefa40 aman20
Chiasốxoàiira10p ha ần xài
Your original equation has no y-variable. It results in x = -2/3 when you solve for x which is a vertical line. Thus, if you want a line parallel to this that goes through point (- 1, - 4), you just set x equal to the x-value in that ordered pair.
Your parallel line is x = - 1.
Answer:
<h3>A) 204m</h3><h3>B) 188m</h3>
Step-by-step explanation:
Given the rocket's height above the surface of the lake given by the function h(t) = -16t^2 + 96t + 60
The velocity of the rocket at its maximum height is zero
v = dh/dt = -32t + 96t
At the maximum height, v = 0
0 = -32t + 96t
32t = 96
t = 96/32
t = 3secs
Substitute t = 3 into the modeled function to get the maximum height
h(3) = -16(3)^2 + 96(3) + 60
h(3) = -16(9)+ 288 + 60
h(3) = -144+ 288 + 60
h(3) = 144 + 60
h(3) = 204
Hence the maximum height reached by the rocket is 204m
Get the height after 2 secs
h(t) = -16t^2 + 96t + 60
when t = 2
h(2) = -16(2)^2 + 96(2) + 60
h(2) = -64+ 192+ 60
h(2) = -4 + 192
h(2) = 188m
Hence the height of the rocket after 2 secs is 188m
Answer:
11/12
Step-by-step explanation:
1/4+2/3
1/4×3/3+2/3×4/4
3/12+8/12
.58 + .15x = 4.78
28 minutes
