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Anvisha [2.4K]
3 years ago
11

Which Meteorite Condition in Space is Similar To What Most Likely Was Present On Early Earth?

Biology
2 answers:
Arlecino [84]3 years ago
5 0

Answer:

The correct answer is -Presence of Inorganic Molecules

Explanation:

Scientists believe that primitive earth contains inorganic molecules in the form of CO, NH₃, H₂O, HCN, CH₄ and these inorganic material converted into organic material like amino acids which are used to make protein.

So simple organic molecules were formed like amino acids, succinic acid, uric acid from inorganic molecules which condensed and polymerized to form macromolecules like proteins, nucleic acids.  

Then these molecules must be aggregated by intermolecular force to form an enclosed sphere called microsphere. These microspheres were cell-like and through natural selection got the ability to divide to form live prokaryotic cells.

Thus the presence of inorganic molecule was important to originate life on earth. Therefore the correct answer is - Presence of Inorganic Molecules.

gavmur [86]3 years ago
3 0
I would say presence of inorganic molecules I THINK not sure.
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SOMEONE PLEASE HELP MEEEEEE
ICE Princess25 [194]

Answer: interphase: 4,5,6,8,11,12,13,14,16,19,20,22

prophase 2,15,21

metaphase 1,10,17

Anaphase 7,18

telophase none

Cytokinesis: 3,9

Explanation:

8 0
3 years ago
Iron-55 has a half-life of 3 years. How much of a 40 gram sample will remain after 12 years? A. 0 grams B. 4 grams C. 2.5 grams
Readme [11.4K]

Answer:

\boxed {\boxed {\sf C. \ 2.5 \ grams }}

Explanation:

We are asked to find how much of a 40 gram sample remains after 12 years.

Iron-55 has a half-life of 3 years. Therefore, after 12 years, 4 half-lives have been completed.

  • 12 years/3 years = 4 half-lives

Every time a half-life is completed, half of the sample's mass decays. Remember we start with a 40 gram sample.

  • 1 half- life: 40 g / 2 = 20 g
  • 2 half-lives: 20 g / 2= 10 g
  • 3 half-lives: 10 g / 2 = 5 g
  • 4 half-lives: 5 g / 2 = 2.5 g

There is also a formula that can be used to solve this problem.

A= A_o(\frac {1}{2})^{\frac{t}{hl}

Where A₀ is the initial amount, t is the time, and hl is the half-life.

We know 40 grams is the inital amount, 12 years is the time, and 3 years is the halflife.

  • A₀= 40 g
  • t= 12
  • hl= 3

A= 40 \ g (\frac{1}{2})^\frac{12}{3}

A= 40 \ g (\frac{1}{2})^4

A= 40 \ g * 0.0625

\bold {A= 2.5 \ g}

After 12 years, <u>2.5 grams </u> of Iron-55 will remain.

4 0
3 years ago
a woman with Type A blood is claiming that a man with Type AB blood is the father of her child who is Type B ? show possible cro
Tpy6a [65]

Answer:

Yes possible

Explanation:

If mother is heterozygous A then her alleles are iA and iO while father is AB so crossing the two we get AO, AA, AB and BO. Hence proved

8 0
3 years ago
What other component does nuclear power utilize in order to
Oliga [24]

Answer:

Explanation: The answer would be water because , nuclear power plant would heat the water so that it could produce steam .

7 0
1 year ago
What chemical helps to regenerate ATP
kaheart [24]

creatine phosphate is the chemical that helps to regenerate ATP

3 0
3 years ago
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