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DerKrebs [107]
3 years ago
13

How do you solve -6x+5t=-30

Mathematics
1 answer:
Sever21 [200]3 years ago
6 0

Answer:

Sonic has the answer

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

t

=

−

1

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Is 4.565565556 rational
Gwar [14]

Answer:

Yes it is.

Step-by-step explanation:

Yes it is.

Rational number is the subset of

  • Whole number(Positive number+0)
  • Natural number(Positive number)
  • Negative number
  • Fraction &
  • Decimal

4.565565556 is a rational number since it's a decimal.

4 0
3 years ago
A sample of 50 drills had a mean lifetime of 12.17 holes drilled when drilling a low-carbon steel. Assume the population standar
zmey [24]

Using the z-distribution, it is found that the 95% confidence interval for the mean lifetime of this type of drill, in holes drilled, is (10.4, 13.94).

We are given the <u>standard deviation for the population</u>, hence, the z-distribution is used. The parameters for the interval is:

  • Sample mean of \overline{x} = 12.17
  • Population standard deviation of \sigma = 6.37
  • Sample size of n = 50.

The margin of error is:

M = z\frac{\sigma}{\sqrt{n}}

In which z is the critical value.

We have to find the critical value, which is z with a p-value of \frac{1 + \alpha}{2}, in which \alpha is the confidence level.

In this problem, \alpha = 0.95, thus, z with a p-value of \frac{1 + 0.95}{2} = 0.975, which means that it is z = 1.96.

Then:

M = 1.96\frac{6.37}{\sqrt{50}} = 1.77

The confidence interval is the <u>sample mean plus/minutes the margin of error</u>, hence:

\overline{x} - M = 12.17 - 1.77 = 10.4

\overline{x} + M = 12.17 + 1.77 = 13.94

The 95% confidence interval for the mean lifetime of this type of drill, in holes drilled, is (10.4, 13.94).

A similar problem is given at brainly.com/question/22596713

6 0
3 years ago
Solve 3-²<br>I need work shown​
skelet666 [1.2K]

\huge\text{Hey there!}

\large\text{Equation: }\bold{3^{-2}}

\large\text{Lets convert }\bold{3^{-2}}\large\text{ into }\bold{3^2}\large\text{ temporarily...}

\large\text{Equation:} \bold{\dfrac{1}{3^2}}\\\\\bold{= \dfrac{1}{3\times3}}\\\\\bold{3\times3\rightarrow9\leftarrow\ solving\ for\ your\ DENOMINATOR\ (bottom\ number)}\\\\\bold{= \dfrac{1}{9}}\\\\\boxed{\boxed{\large\text{Answer: }\bold{\dfrac{1}{9}}}}\huge\checkmark

\textsf{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

3 0
3 years ago
a jug for a baseball team holds 20 gallons of water to make an energy drink one cup of mix is used for every 2 gallons of water
Solnce55 [7]
Assuming that the mix disolves into the 20 gallons and doesn't take up space

1:2
x:20
1/2=x/20
multiply btoh sides by 20
10=x

answer is 10 cups of mixture
5 0
3 years ago
The price of a computer component is decreasing at a rate of 15​% per year. State whether this decrease is linear or exponential
Margaret [11]

Answer:

Since the price is given by an exponential function, the decline in price is exponential.

The component will cost $36.8475 in three years.

Step-by-step explanation:

The equation for the price of a component has the following format:

P(t) = P(0)(1-r)^{t}

In which P(t) is the price after t years, P(0) is the initial price, and r is the rate that the price decreases.

Since the price is given by an exponential function, the decline in price is exponential.

The price of a computer component is decreasing at a rate of 15​% per year.

This means that r = 0.15

Component costs ​$60 ​today

So P(0) = 60. Then

P(t) = P(0)(1-r)^{t}

P(t) = 60(1-0.15)^{t}

P(t) = 60(0.85)^{t}

What will it cost in three​ years?

This is P(3).

P(t) = 60(0.85)^{t}

P(3) = 60(0.85)^{3} = 36.8475

The component will cost $36.8475 in three years.

6 0
3 years ago
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