How do I find the symmetry

Mathematics

1 answer:

Novay_Z [31]3 years ago

3 0

Symmetry is the same as the one side of the graph but it is fliped on the X-axis

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BD bisects LABC. Solve for x and find m2ABC. m_ABD = 4x-2, mZCBD=2x + 6

Sholpan [36]

Answer:

i) x = 4°

ii) <ABC = 28°

Step-by-step explanation:

Given that BD bisects <ABC then it is true to say that;

Angle m < ABD=m < CBD

Hence;

4x-2 = 2x +6

4x-2x = 6 +2

2x = 8

x=8/2 = 4

x= 4°

Hence

Angle m< ABD = 4x-2 = 4*4 -2 = 16-2 =14°

Angle m < ABC = 2* 14° = 28°

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3 years ago

The sweets bakery makes 156 dozen cookies per day. How many individual are baked each day

miv72 [106K]

Step-by-step explanation:

Im assuming you mean the number of individual cookies which are baked each day, since we all know that a dozen is 12, the answer to this question can be simply derived from multiplication of 156 and 12, so basically you just multiply 12 and 156 and you get your answer,

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3 years ago

If y(x) = 3(x+5) +4/x, what is f(a+ 2)?

Lerok [7]

Answer:

Step-by-step explanation:

Theyre basically telling you that x = (a + 2)

All you have to do is replace x with a + 2

$f(a+2)=3(a+2+5)+\frac{4}{a+2}$

Next you have to simplify, 2+5 = 7 to get 3(a+7). Apply the distributive property to get 3a + 21. Your new equation is now:

$f(a+2)=(3a+21)+\frac{4}{a+2}$

Now here's the issue, you cant add those two terms yet because we need a common denominator. Multiply the numerator and denominator of 3a + 21 by a+2 to get:

$=\frac{(a+2)(3a+21)}{a+2} +\frac{4}{a+2}$